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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& E5 Y! s, f8 R3 T) s: q5 `0 P& k- }
共四堆5.39.217.77+ B" R) p( S# _3 u. k4 P9 U% W
称两次得出异常的在那一堆,其轻重: H/ ?  w* o: }0 S
在异常的那一堆中在称一次' {# Q: U/ U: h# R. e
就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb* N  N, Y+ B% v2 t
weight any 2 sets.5.39.217.77/ L: H6 Z. j# H) k0 \* g" r7 I
if the 2 sets are equal, then you know the heavy one is in the third" N$ U4 _2 l1 ^3 s0 d
if one of the 2 is heavier, then the heavy one is in that set$ D$ b1 i! `0 @) R* u3 X
then divide the 4 balls into 2.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。0 T3 s9 D8 \+ w& S6 W
weigh themTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& I0 e( ?* G- ~. X1 @
and divide the heavier into 1! c( d: G& A! k
and weight them.
; r7 o/ n5 v' t% P! Q2 P+ Etvb now,tvbnow,bttvb3 x weighing and get the ans.  8 @6 I  r+ G0 W* m# ]+ E  a& |7 D
in less than 15 secs.
1. 6 aside and weight.
4 J/ e6 P' H* K& c) K2. heavier side from (1), 3 aside weight again.
5 V4 C3 D! l4 f, D% E3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.773 }1 ?' p# S, k% Q7 a( `
tvb now,tvbnow,bttvb' V; }; u9 `1 O6 t
but i have a question. 重量異常 can be heavier or lighter.... so......
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