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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb3 |4 I) x* N8 E' J+ o: u; R  R
共四堆5.39.217.77; B5 m1 v1 J- z* r5 R
称两次得出异常的在那一堆,其轻重公仔箱論壇$ t4 E- E* w6 p+ F0 S0 w- C
在异常的那一堆中在称一次公仔箱論壇4 V6 @; }: q) i( W
就可以找到了
divde the 12 balls into 3 sets of 4.
9 Z& _2 j$ x% D9 b5 _+ ~TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.
8 g; |2 [! ], x: c. l; Y  Z% i8 E, @) [公仔箱論壇if the 2 sets are equal, then you know the heavy one is in the third5.39.217.77/ T* t6 i8 `( F9 q( j" D: T! D6 B
if one of the 2 is heavier, then the heavy one is in that settvb now,tvbnow,bttvb: |* m! C8 x  D5 n. y
then divide the 4 balls into 2.( R/ B* A) y: T" Y* k
weigh them
- @* n: n9 Z2 I+ Z& H: K/ }* t3 Land divide the heavier into 1; K7 E9 d% J6 L: }1 k: @9 B5 @9 T
and weight them.
) t- l3 Y2 [. @! p+ btvb now,tvbnow,bttvb3 x weighing and get the ans.  
2 }( \. Q) l- O) Qtvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.tvb now,tvbnow,bttvb$ S* x: ^& p; u* Q9 t
2. heavier side from (1), 3 aside weight again.公仔箱論壇, O: v' X2 E5 Y% q4 ?
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
/ q! Y& F2 _( l8 S% m5 ]0 F5.39.217.77
6 K, b+ `" m% C1 u: F% [5.39.217.77but i have a question. 重量異常 can be heavier or lighter.... so......
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