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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
6 j  b" U; |( |1 l$ t. b' y共四堆
& {: |  |  p9 b6 b$ ]4 D$ g) y称两次得出异常的在那一堆,其轻重
- X4 W2 t1 O2 T0 ~( O7 b- o8 u4 ^& E2 d在异常的那一堆中在称一次
& U# H& S; L7 m) _0 n  T1 n就可以找到了
divde the 12 balls into 3 sets of 4. 公仔箱論壇& L8 m. Y, [/ P. Z0 D( i% ^3 B
weight any 2 sets.
$ x/ Q& j5 ~4 S3 h9 ^) x9 v6 Zif the 2 sets are equal, then you know the heavy one is in the third
2 s3 ~& `; B( ]TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if one of the 2 is heavier, then the heavy one is in that set
0 G% @% v3 q/ j. l: F5.39.217.77then divide the 4 balls into 2.
8 R% x5 o4 G% a' {+ I" A+ Eweigh them/ p& q. r; _3 U5 g
and divide the heavier into 1
# q+ T  ]9 o9 v7 M/ i$ x0 b1 |- ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。and weight them.
- z3 x( ~3 N, f3 x weighing and get the ans.  
% E7 ^3 j  V# M# wTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.
: `5 ~, W9 N/ h" q! I6 `2. heavier side from (1), 3 aside weight again.* J/ }& V( x. X# L$ e
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
% h+ ?8 F  N1 b
1 `+ @0 J4 A1 x) K. y% ]but i have a question. 重量異常 can be heavier or lighter.... so......
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