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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆6 z0 \$ A' u/ t0 c3 z
共四堆tvb now,tvbnow,bttvb% \. \6 u4 Z4 W
称两次得出异常的在那一堆,其轻重
3 ~! S" B0 G( c1 h; H" B在异常的那一堆中在称一次5.39.217.775 L" p; Q' t2 v5 G' j
就可以找到了
divde the 12 balls into 3 sets of 4.
0 s3 Y6 `. [- m' Z. L1 r3 p4 _6 \. \& p5.39.217.77weight any 2 sets.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 V  J0 M, M. W# x) B5 r
if the 2 sets are equal, then you know the heavy one is in the third
, O6 O+ Y7 W5 j& c$ j5.39.217.77if one of the 2 is heavier, then the heavy one is in that set3 S' [+ i8 ]) q3 M0 W7 B0 X) q
then divide the 4 balls into 2.
8 k3 A7 E. h" _weigh them5.39.217.77' J2 b) R1 \$ G; b. W: g
and divide the heavier into 1
5 z' U& S/ \- ?+ ]and weight them.
- j9 L& @# c  x8 k% A1 {tvb now,tvbnow,bttvb3 x weighing and get the ans.  
9 T$ O% B$ p7 I0 _0 l* ]: FTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight." m! X9 B% l9 }% u9 ^, c
2. heavier side from (1), 3 aside weight again.% p* v' j) T7 Z
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. ' X$ T* x: q! p  }5 d; y) o: O* S$ T
5.39.217.779 J* s$ l4 x9 P: R6 I6 D/ `  Z! H
but i have a question. 重量異常 can be heavier or lighter.... so......
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