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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.77' N/ V- j: i. i. F# f
共四堆$ Q' \! _* c- m/ c4 d3 j7 G
称两次得出异常的在那一堆,其轻重公仔箱論壇$ X) D( l, z# u0 i
在异常的那一堆中在称一次
( @% Z9 O( V' b7 D% O* ctvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4.
' C1 K4 r) J$ t5.39.217.77weight any 2 sets.  v7 c7 g0 y$ s
if the 2 sets are equal, then you know the heavy one is in the third8 [: w( R) \" t6 c7 }& ]
if one of the 2 is heavier, then the heavy one is in that set
* ]6 J, j1 x5 G公仔箱論壇then divide the 4 balls into 2., p9 b: [0 g3 x; O2 Q+ E
weigh them& Q+ ]; ?$ x4 g# k0 K6 ?
and divide the heavier into 1
3 C1 s) H( e, H# J7 W' c" Ftvb now,tvbnow,bttvband weight them.0 Y) O$ l/ y0 r4 e* |* J
3 x weighing and get the ans.  tvb now,tvbnow,bttvb- ]9 K3 K- k+ m# f* Q$ E$ H
in less than 15 secs.
1. 6 aside and weight.
# \5 ]- }3 k! _$ e1 A& Ltvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.
4 ~& S; v* y3 S6 U3 E& G8 Z% F3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5 d' @2 U; x3 K
公仔箱論壇/ @' W' M& o# ^
but i have a question. 重量異常 can be heavier or lighter.... so......
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