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好難呀...
難...
好難呀....
ddd
好難喎
There is 12 balls.. divide them into piles of 41 T/ e6 O5 n, Y! q/ e( J) ~
so 3 groups for 4..name is A,B,C
* S7 n2 c* \1 s; [0 \$ @tvb now,tvbnow,bttvbcase 1: : B. O6 N5 [; a" ~5 q6 ~
measure A -- B 8 S3 A+ f+ }  `8 C# q/ b. W0 W
A or B is heavier tvb now,tvbnow,bttvb8 u* A1 h2 h; U" j' W! P# Y
divide that group into 2 by 2' m# z% @0 [; R' l. Y+ z. j
then divide heavier group into 1 by 1- m. f6 ~5 p+ {, o) e6 M$ K
; f. Q1 y3 R+ U% p2 t" t8 `9 K
case 2:
& O. H' r" p# e' ^0 @& r公仔箱論壇A and B is the same.. therefore C has the heavier ball公仔箱論壇* h* I1 V& b& H5 X0 U: U7 h% C
divide C into 2 by 2
7 d$ v# ^" ^% n. l) e2 ]1 Ktvb now,tvbnow,bttvbthen divide heavier group into 1 by 1... q9 h  l* M4 K1 T: }" ]) n1 l

. M- u/ N& s; P公仔箱論壇got it in 30 seconds.. not so hard -.-'
thx
i got it.... separate into 4 group 3(a)3(b)3(c)3(d), weight 2 of them(a,b), if it is the same, weigh b and c, if they are the same too... then the different ball must be in group d. if you weight different, you identify that group according to the different group. Also, we know the the different ball is heavier or lighter.
1 R% P; Q+ ]# a$ E& v; i
8 b; F/ p$ O7 X( X% u% ?; M7 O公仔箱論壇they separate into 3 group111, weight 2 of them. if they are the same, the extra ball will be the different ball. if they are different, the heavier/ lighter ball will be the different one according to the previous weight.
睇下先
do this is so boring...
9 R1 R% Y/ o$ ?* q* e9 Y( {. {* v! l公仔箱論壇play game la~~~
[-X OK la^:)^ ^:)^
一知道有答案睇就唔想谂咁耐了
?
why?
多謝大大的分享
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