fatgal5

十二個球分成三組,
# a/ `" x. L5 [5.39.217.77每組有四個球,
/ ]4 q( |! b  n+ E, h& y* k# {9 Ztvb now,tvbnow,bttvb是旦羅兩組來稱, 因為這個是"一部沒有砝碼的天平", 所以如果重量一樣, 個天平是會平行!(1次)
5 x. N: Q! m! h$ B0 O如果里兩組平行,
, l/ ~4 q2 K% p就將靜下來個組分,再分成兩組各有兩個球,A和B
* S) C3 u9 m; S9 f) L& @將A組稱,(2次)一樣天平原理, 如果平行的話
+ Z( X: Z1 _/ c5 f3 g7 m1 U, M/ O5.39.217.77咁!個球一定係B組到, 冉稱最後一次,就知邊一邊有異常.

iankcng

呢啲都算IQ題

tommyin

玩咩，咁都係難題，唔係化

yfellow

我去見工的時候那個人問過我這個問題... 我就用blackberry send email 俾我老婆, 佢几分鐘就找到了答案...  但係... 佢之前是沒有接觸過言題的...

eric.hau

做出來了  = =
4 b& {3 O3 ]" j7 a: A$ R公仔箱論壇以前就做過了^^
, `4 m- `3 p& Z8 Q" f: ]6 _; p; M花不到1分鐘

saviola7

无解,不知道那个球是比较重还是轻.s上面的答案根本就是错的.

mkc_asia

故國作~

景天

????

moneyking

Let me see!

Magen

ok

qwera1

好难。。。

qwera1

好難呀．．．．

笨霜1

11111111111

cmc272

分half

tincan

First put 6 balls on each side and weight them. TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。! C4 g: {, `+ n0 q
Take the heavier 6 balls, split them into 2 groups of 3, and weight them again.
* V) F! ?2 d% b3 I' J3 E+ b! \tvb now,tvbnow,bttvbTake 2 out of the 3 heavier balls and weight them. If one of them is heavier than the other, then that one is the target that we were looking for. If both of the balls have the same weight, then the remaining unweighted ball is the target.
6 p- X9 U9 Z8 z0 E
2 n: |4 b2 ~4 C1 ktvb now,tvbnow,bttvb
6 ^6 G; v$ G0 K  D8 I  r9 stvb now,tvbnow,bttvbOoops, I got it wrong. @@
- p0 U. E/ X" A! atvb now,tvbnow,bttvb% G: Q1 R' W+ O6 Y3 r) \
[ 本帖最後由 tincan 於 2007-3-26 05:17 PM 編輯 ]