twinsdragon

That is a very simple mathematics question.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。& w  p# p* K6 d' r2 @
Let x = Male, y = Female, z = Child
! e* R+ y+ |' ^/ q3 S- qtvb now,tvbnow,bttvb6x + 3y + z/2 = 100   Formula 1
0 @: q$ Z1 e4 p9 y. |2 Ntvb now,tvbnow,bttvbx + y + z = 100    Formula 2tvb now,tvbnow,bttvb$ u, S( X  R2 g' A+ `9 k
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3* ~5 ?) F/ F: e2 a
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。' q( A7 D7 O# y, h! r
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.777 V6 I* z1 {5 H) S* R* g
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.$ Z1 Z" Q. S5 R0 r7 A) N
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77% p5 {. l7 N3 ~
Eventually, the answer is 20 female and 80 children and no male.