That is a very simple mathematics question., Q* b) s1 F7 \+ m2 x" ]
Let x = Male, y = Female, z = Child5.39.217.771 n0 }4 M- c1 G. x, F
6x + 3y + z/2 = 100 Formula 1
, X9 Q. M$ d6 P: d/ D; vx + y + z = 100 Formula 29 J( w1 l. _1 I# ^
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
6 g" T4 `. ^0 a. j; u5.39.217.77Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
# y" l' w: w2 r5 LTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5
! a0 o5 g) A0 w9 R2 o公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.77& \6 Q; m X- X4 i
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb/ v. L4 |6 n2 Y+ Y; v$ U+ H
Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:40 PM
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