twinsdragon

That is a very simple mathematics question.: U0 Y# x+ T9 j
Let x = Male, y = Female, z = Child5.39.217.77& f: j# q  V  e. g; `
6x + 3y + z/2 = 100   Formula 1
* L% M1 r' M& ^公仔箱論壇x + y + z = 100    Formula 2
4 w; I5 h  j. G& A6 W1 @1 ~* T5.39.217.77Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
4 K6 {! c& t" W+ B. o) U公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
/ |% n& T) v# `: @2 w8 v1 Q公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5( M4 E7 z& F7 u7 g: G
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
0 d( d( d& D$ OTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
8 Y- P0 v& p3 B& m' u$ zTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male.