twinsdragon

That is a very simple mathematics question.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。) j, A6 t( F8 ^, I. C& T2 M2 o
Let x = Male, y = Female, z = Child
. A, p; d4 M9 Z公仔箱論壇6x + 3y + z/2 = 100   Formula 19 R1 I+ l4 g% L# \/ |' y! D! o6 Z3 }5 u
x + y + z = 100    Formula 2
- y* F0 Y2 [2 R! _5 A" ]/ WSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
* {2 N2 B3 n) e! U/ ~Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb4 H# _. i  Q  p. `" z7 C$ y
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.770 N! D  I9 C/ @8 v
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.7 H7 B4 a# F/ Z: p! k6 p( C
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
1 z/ K- k- @" f6 B! ^6 K2 a7 U5.39.217.77Eventually, the answer is 20 female and 80 children and no male.