That is a very simple mathematics question.
7 G) s: F h5 \- L( I% O' h1 xTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child
# I& A3 c n9 i# A3 \tvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
+ n& Z% \, W y) F# {公仔箱論壇x + y + z = 100 Formula 2
, V- x8 x; L0 C- W) {1 _5 yTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
* G* N8 D" Q8 ~' g( I3 W$ eSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb* m) M7 ?7 t9 f0 i( }$ r; N5 b
Formula 4 can change into 11x + 5y = 100 Formula 5
, n8 @& L" h9 G7 U: U5.39.217.77In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.7 m0 P6 O$ E) j( y; _4 A: d
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77) w n7 [4 y/ q+ }
Eventually, the answer is 20 female and 80 children and no male. |