That is a very simple mathematics question.
+ _+ C2 x' h9 j2 TLet x = Male, y = Female, z = Child
- D9 T( L& [, K( H$ BTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6x + 3y + z/2 = 100 Formula 1, _9 d/ s- T0 z% t, `
x + y + z = 100 Formula 2
2 V) O, v4 B% @* Z% QSimplify Formula 2 into z, we get z = 100 - x - y Formula 3, q8 Y! ?. R; I
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 48 D5 E% I7 ~, n* W# n
Formula 4 can change into 11x + 5y = 100 Formula 5
, `+ k0 }0 }& Y. q) LIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.( R" T5 c8 E% k( _% L1 k) T9 |
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
$ E+ U7 J, s: O# ?8 j$ L2 S0 H/ Jtvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male. |