That is a very simple mathematics question.
' B$ H! e# r! z1 R' S6 g) [+ `Let x = Male, y = Female, z = Child
! D! P/ b' M7 L n; S6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb- g$ K/ j, y3 e! B
x + y + z = 100 Formula 2
4 |6 r3 C! n) c0 c( xtvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb* h( v: C/ O) Q" t
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
" {- w( b2 m' M( w( x公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5& `$ H" p+ @6 ? V
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
0 x& Q: u2 {' o6 ?: C4 m" b2 OAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。8 d1 l* ?, Z( B* ?4 I' K
Eventually, the answer is 20 female and 80 children and no male. |