That is a very simple mathematics question.) z4 y! K( a6 w: e* i
Let x = Male, y = Female, z = Child4 v6 ^8 F9 h* T; ?
6x + 3y + z/2 = 100 Formula 1+ k) U# T5 V0 _( ^/ ^
x + y + z = 100 Formula 2公仔箱論壇& D, y8 s; M9 y/ E, s; \ \& O
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3* D. F/ ^% q4 A- h A/ g
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
. F5 d$ X- w9 e- F7 W) ?5.39.217.77Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb+ A% |7 ~7 Y5 i. ~ b
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇& _, D, a/ Y! b1 _; w2 O+ N7 s
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。, ]$ v6 L+ \! C& Y8 {/ P d" g7 O
Eventually, the answer is 20 female and 80 children and no male. |