| That is a very simple mathematics question.; ]; g$ m4 \* l9 @" R Let x = Male, y = Female, z = Child公仔箱論壇" e" R, u9 I7 D$ r
 6x + 3y + z/2 = 100   Formula 1
 9 G, t5 g. T: j" A$ ~, c% iTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。x + y + z = 100    Formula 2tvb now,tvbnow,bttvb3 N1 k3 m' w- H9 r& c9 r/ f4 N
 Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
 0 G( M4 R( d' s7 g& d2 z/ kSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 45.39.217.774 v$ ^9 N$ u: y; A
 Formula 4 can change into 11x + 5y = 100 Formula 5
 7 Q9 |6 C& @) F: \+ L9 W1 U: jtvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
 - u/ @# A4 e# y- X; s' O: Ztvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
 7 d, W% \7 N$ P8 Q; p+ P* }Eventually, the answer is 20 female and 80 children and no male.
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