返回列表 回復 發帖
不知道
why
看答案
let the 12 balls be numbered 1,2,3,4,5,...,125.39.217.77. g/ S! r5 }6 `$ s$ ]/ j' u2 X7 g
weight 1234 with 5678
7 I% \4 m% Z5 V3 S7 P. L! D& c% L  l: \5.39.217.77case 1  _6 R6 P) V" Q3 W0 G9 A
if 1234>5678, then weight 125 with 6785.39.217.77( k' c" B, E4 N! ]8 \% _
if 125>678, then weight 1 with 2
% {" s! l% _7 \% N" b! }2 |5.39.217.77if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2
% x0 i5 Z& V) w" m6 ]5 Jif 125=678, then weight 3 with 95.39.217.77+ _+ e0 b+ F6 |. @$ W6 K
if 3=9 it is 4, else it is 3
4 t) X, |; O0 a- n' S& P5 b$ Q5.39.217.77if 125<678, then ewight 3 with 4
$ K2 y+ s$ \0 H+ |) S1 yTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4公仔箱論壇( R- Y0 x9 v" V  e% S' g

1 T! R- @9 C( f& d7 o1 J5 rcase 2
8 [4 h3 {- K. A& w( t) RTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。repeat above for 5678 instead of 1234 if 1234<5678
+ r' d$ ~$ L+ f* ?6 s公仔箱論壇, l2 ]/ m7 E( v
case 35.39.217.77  x' ?3 p  T+ x
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain% f1 R2 e- R5 Q7 t6 h* W5 h
- [! n8 C6 q. H+ d  c
[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ]
thx
how?
the ball's weight is abnormal than other, not only heaver than other

回復第 1 帖由 MagicAndy 所發的帖子

好贴啊~~~
我都諗到.. 但唔知岩唔岩
实在想不出了
=.=
CC
太简单了吧?
cc
返回列表