put six on each side first
9 z! a' ?7 x3 I* V7 N; t" ztvb now,tvbnow,bttvb& `0 c: g: ]) i0 c4 Y) j [% R8 H
from the heavier six, split it to three on each side
% L' `0 D2 i' l- _5 p" V
! ~* y+ Q% E. X2 K5.39.217.77then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |