put six on each side first( L0 F4 b- ]# ~- G6 U% q, t
; \( r1 O' |3 H) wfrom the heavier six, split it to three on each side1 [$ k6 [6 ^& e* V+ [
: D% }) o* y# I( dtvb now,tvbnow,bttvbthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |