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seesee
為什麼a ?
lets see
123123
i ve done it in 5mins bor......
try try sin
好難呀,thx for share,謝謝大大:014:
first, compare 6 and another 6. they must have difference.
6 F/ m3 J( W0 n9 |0 ?- D0 Z) P5.39.217.77second, divide those 6 heavier one into two, each has 3. u will find difference again.: k4 {3 y( U) O/ c, O0 n
third time, if u put 2 and they are equal, u will know the different one.
% s* a+ [" D+ W5 zso easy....
the answer is?

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thanks for share
睇下先...
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原帖由 stupid818 於 2008-4-17 11:42 PM 發表 $ {$ U( k6 u' I) k$ n. G
first, compare 6 and another 6. they must have difference. tvb now,tvbnow,bttvb: {' {6 _0 }. Z' O- t
second, divide those 6 heavier one into two, each has 3. u will find difference again.2 m  \( }7 T; V5 S3 G
third time, if u put 2 and they are equal, u will kno ...
7 s7 Q5 a: W0 [3 P- g+ utvb now,tvbnow,bttvb5.39.217.77# u$ n* q/ x4 t, \8 `& }
but the question has not defined whether the abnormal ball is heavier or ligher than normal ones ....
貌似很簡單,搞定了。
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