hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^5.39.217.77, f9 I; ]- p6 `5 q; D" M
1st u divide the ball into two group (i group 6 ball)
: @5 z5 I/ }! v% X' R5 @" y; \then 称 them c which side is the heavy TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。$ ^0 {5 g" }( I/ o$ j6 G
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
0 [4 U+ L: e1 i: ]$ g/ q& I3 l公仔箱論壇if not balance take the heavy and then
9 j4 G' s" n0 _4 E# rtake the heavy group divided into 2 group i group contain 1 ball than 称 it
- c( x, q6 l& r. z$ {  Q0 `公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 5.39.217.77% n7 R# Y( z: |) f
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
8 V+ f: E( B- S* ]7 B5.39.217.77然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me