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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
) H0 k- ]4 {* d* |1st u divide the ball into two group (i group 6 ball)
: m4 Z* D- C- |! }4 v9 QTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。then 称 them c which side is the heavy
4 i" \, v- T8 X4 jthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
$ n: p, i) E2 \0 Gif not balance take the heavy and then
6 d+ |9 m' z6 q/ a. d6 G公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it , X7 i' [) L: k0 [5 X( o( M8 [
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: " b, |' ]! R" T+ w
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
' f' d; N. v) n/ X& g' A; J公仔箱論壇然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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