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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^公仔箱論壇3 k' o6 ?$ K. K  K. q: r/ s
1st u divide the ball into two group (i group 6 ball)
, h! m0 [. }1 D+ }  ?& @/ ]! A8 Mtvb now,tvbnow,bttvbthen 称 them c which side is the heavy
  h# H3 h! Y2 g5 h; x# Qtvb now,tvbnow,bttvbthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
3 |" S$ |' f# L6 [, V! b( Y5.39.217.77if not balance take the heavy and then ) P' O) y3 r, H* V1 T: ~! R
take the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb3 {- @1 A' A# ~$ n4 c( @; j, g+ c* o
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
, R: C! C. s3 [% Q1 h3 j公仔箱論壇(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
6 Y) R( r" m/ [5.39.217.77然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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