hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
% g& P+ o, E( X3 |* G; h9 Qtvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)7 K8 C9 z7 g" l, s, i2 g: V
then 称 them c which side is the heavy
! L" T" Q0 S. [: [8 {0 mthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
5 n) O2 p7 e: @if not balance take the heavy and then ! _9 [/ K' j! i0 \6 o, _
take the heavy group divided into 2 group i group contain 1 ball than 称 it 3 z' A( E9 ~' W$ j( z  \
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇; Y: \0 R7 g5 _& [
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边tvb now,tvbnow,bttvb3 \& y- s* ^5 ]# m' j+ b
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me