hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb  z2 l2 ?  X5 q3 n8 w
1st u divide the ball into two group (i group 6 ball)" D; l- v8 e5 h4 I( d$ b. }2 m6 ]1 G
then 称 them c which side is the heavy 3 J+ H# \9 Y6 U: q$ m& C: P
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
: V: ]7 l' w7 {$ nif not balance take the heavy and then 9 V& k# z$ ^! y2 d9 U
take the heavy group divided into 2 group i group contain 1 ball than 称 it " \2 o" U/ I# [9 D( E
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: ) G1 K2 r* W7 a; ]0 [# I
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边公仔箱論壇! \# a2 i" k. k. H; [
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me