hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
' R/ ?( k0 Z. _  G9 xtvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)5.39.217.770 s# r- W& N' j" a
then 称 them c which side is the heavy 9 w2 w3 J3 k; K1 I
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
$ A5 G1 v( n8 d9 ]& G- \if not balance take the heavy and then tvb now,tvbnow,bttvb9 O( P: c; \, c( e- _( j# Z0 a$ S: @
take the heavy group divided into 2 group i group contain 1 ball than 称 it
2 n0 F, P. e+ j% S; \% E( Ltvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 5.39.217.77, i0 P4 Z7 s/ F. [1 Z# v" P/ M
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
5 t3 `0 f3 i+ K, S然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me