i noe de ans cauz 1 do b4 already ^^
0 x' }$ n2 s* C1 u; ~- D* ?1st u divide the ball into two group (i group 6 ball)
8 H6 w7 y- Y$ |! Mthen 称 them c which side is the heavy 4 x3 w0 @. R% a
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
' ?; k7 c9 O5 F. p6 R3 p- A. E5.39.217.77if not balance take the heavy and then
5 z% U: J1 c; d9 B9 x7 |) g( Ptvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb9 _. q7 D: i$ N( g; J5 }3 J) \
than the heavy ball is the ball u wan |