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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
4 ^3 c  S9 G8 }/ ?$ I2 g8 `2 ]1st u divide the ball into two group (i group 6 ball)
! T; ^9 ^* c5 ?3 K! ~* \! [) T公仔箱論壇then 称 them c which side is the heavy 2 i; x! V* S( L( c; b& Z2 m
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 5.39.217.77- |) W4 y4 N' h( _- ~/ V' z
if not balance take the heavy and then
( y$ h* f7 H( U& z$ S# W5.39.217.77take the heavy group divided into 2 group i group contain 1 ball than 称 it 5.39.217.77  G( t" {% ]9 E8 {9 [6 E
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
# g3 s  W3 K1 G0 f7 e5.39.217.77(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边( `8 T0 L2 m) A2 m
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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