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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.77:8898& v- n  @* r3 j. a* [& N! ]
共四堆
- x  p1 |# Y+ W$ P7 G4 E' h/ ttvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb5 C2 ?, S4 a/ j9 X
在异常的那一堆中在称一次5 a( f( L4 i+ a5 ~. Z
就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.77:8898$ Z: j& X4 r, I9 T! U- ~* d  T
weight any 2 sets.
* x$ y/ A6 ]& n8 ^! S9 g: Etvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third3 s; z* M* F. l# f1 Y' C0 G. L$ i# B
if one of the 2 is heavier, then the heavy one is in that settvb now,tvbnow,bttvb* i% S( |3 h+ y& W/ i$ l# b6 [
then divide the 4 balls into 2.
0 y4 E+ C# t+ n  e5.39.217.77:8898weigh them
" y" S1 Q0 \3 u$ |5.39.217.77:8898and divide the heavier into 1
) C  a3 q. @- \7 G* u% T, t; H" v5.39.217.77:8898and weight them.公仔箱論壇) L4 S' b- E: n! n3 w
3 x weighing and get the ans.  
3 Y+ q2 l( l) D6 B8 hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.公仔箱論壇/ v0 o1 B3 L3 G# V/ e, m
2. heavier side from (1), 3 aside weight again.5.39.217.77:8898# d" \8 e- q5 H+ C" l5 u
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. / }$ n8 Y1 f( }
tvb now,tvbnow,bttvb6 A5 }* M9 S( e' Q" N/ J+ q
but i have a question. 重量異常 can be heavier or lighter.... so......
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