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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
0 `7 _8 P7 R9 q9 Z$ j6 c# n9 Q. X公仔箱論壇共四堆tvb now,tvbnow,bttvb% f. S# A% Y/ y
称两次得出异常的在那一堆,其轻重* g6 b, P3 g  ?$ `$ h' N( i
在异常的那一堆中在称一次公仔箱論壇2 q% ~5 o6 O. Z+ U) Z1 W/ |$ C* @" {
就可以找到了
divde the 12 balls into 3 sets of 4.
) |1 ]" s- u- s1 E) oweight any 2 sets.公仔箱論壇# F! u9 B% A, V9 h; H3 a, z- e
if the 2 sets are equal, then you know the heavy one is in the third
5 @" G5 B% M( Y$ l' v+ ~if one of the 2 is heavier, then the heavy one is in that set
) P$ A/ k) D8 O7 M; vtvb now,tvbnow,bttvbthen divide the 4 balls into 2.
% L6 D1 K! K7 ]weigh them
9 j9 t6 {( V! v公仔箱論壇and divide the heavier into 1
" d; l/ y1 E/ h# Btvb now,tvbnow,bttvband weight them.
& Z, J9 T: `0 V  Z' m3 G3 R4 D% [公仔箱論壇3 x weighing and get the ans.  5.39.217.77:8898% Q' t2 {! m5 |  @2 M, P5 c
in less than 15 secs.
1. 6 aside and weight.
" q' R  P/ y+ z1 H- ?5 V5.39.217.77:88982. heavier side from (1), 3 aside weight again.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。; G( Z$ j* W. M$ g( B+ ~8 P
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. . _" V7 {' M3 N( {1 ^( Y3 t% I) H
4 L' b4 M/ X3 K
but i have a question. 重量異常 can be heavier or lighter.... so......
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