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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.77:8898$ I; h8 g9 }4 }- W$ L0 N
共四堆
6 s: p; U, {9 [* ^称两次得出异常的在那一堆,其轻重6 c1 n9 `/ c+ r; x2 V1 g. |
在异常的那一堆中在称一次5.39.217.77:8898% \! c6 A2 f* j7 _: _7 D
就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb$ m, c: ?2 c; `' P  \* a/ b
weight any 2 sets.5.39.217.77:8898: H6 t$ o6 Y+ p2 r; ~8 k
if the 2 sets are equal, then you know the heavy one is in the third
% d5 R7 `/ ~) P5 C  ?$ |" t8 j- a$ qif one of the 2 is heavier, then the heavy one is in that set8 C% H4 W, X# h, V1 ~
then divide the 4 balls into 2.
: t& t6 m( F( f4 N9 Tweigh them) P! \4 s6 m% G: ]
and divide the heavier into 1
( a" H' n* N# R! m. l/ v" E- Itvb now,tvbnow,bttvband weight them.tvb now,tvbnow,bttvb! P1 J5 Y/ z- }9 n4 X
3 x weighing and get the ans.  
" w4 s& D; K- r# e' k( i8 i' x/ Jtvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.公仔箱論壇4 Y5 s$ o. C) A: ^" r* ?4 f0 }  e
2. heavier side from (1), 3 aside weight again.6 F1 B8 Q+ Y1 |# L/ B! r8 D
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
, x6 Z. R4 f& Mtvb now,tvbnow,bttvb
! C: B/ Z( [. q. a1 B# _0 E+ NTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。but i have a question. 重量異常 can be heavier or lighter.... so......
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