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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆* J9 ?' y; @4 c, m0 `6 F/ I, ]
共四堆
, r- x" M4 |! zTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。称两次得出异常的在那一堆,其轻重5.39.217.77:88982 T3 E+ C; W- \
在异常的那一堆中在称一次
. n* {* e& Z, A' Z/ T& C5 W) }7 H公仔箱論壇就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb+ B, U* k7 R! M. g' S
weight any 2 sets.
# x5 j$ L! v' f3 tif the 2 sets are equal, then you know the heavy one is in the third
3 \5 }& t% I2 S* O: V/ Atvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that set
5 S) h- B+ v" p* q5 K; F) Xthen divide the 4 balls into 2.
5 b" }0 j. v! V7 q公仔箱論壇weigh them
" u2 F+ D3 W' T+ o3 O/ _, ]and divide the heavier into 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。' \" a: b6 g+ Z$ w% k
and weight them.tvb now,tvbnow,bttvb5 c$ `  J" e, l
3 x weighing and get the ans.  
4 x* f2 {6 z: w" E: n1 N+ B* l1 Kin less than 15 secs.
1. 6 aside and weight.6 T1 q* t9 r/ y; K' o! _% j
2. heavier side from (1), 3 aside weight again.
, b. ~) E/ b1 w4 N8 L' A5 U8 q9 `& y3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
$ p( H& O& O" L! w% A" o/ N5.39.217.77:8898( s' U7 |7 j/ @. n+ C# }. O
but i have a question. 重量異常 can be heavier or lighter.... so......
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