zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
! \' i$ M8 I2 B+ A# L- W4 P将比较重的那份再平均分成两份成一次
9 D9 v/ V8 B! ?/ J) o公仔箱論壇剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 45.39.217.77:8898% K* @9 [$ L  A: R1 m  a
if  (4v4)= same that means the rest of 4 is got more weight+ @1 X1 t) S  C7 `9 {0 `+ }8 v4 n
    then goto 2 - compare rest of(4)  - 2 with 2 5.39.217.77:8898; E' V/ D& a, T5 i5 v. d0 K
           if (left side is more weight)5.39.217.77:8898. n. A' V) X7 ^
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
3 L2 u! ?% v. O8 }) s          else ( right side is more weight)5.39.217.77:88984 E& s" M; z  L, h* y& c; Z
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
: \' s. q. s- {8 Y2 J公仔箱論壇else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。