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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次tvb now,tvbnow,bttvb* V0 |! J' U4 S1 ?
将比较重的那份再平均分成两份成一次+ o  G& a: i* j2 y( Y- }2 |
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
1 n" l; X% W2 Y; ~: ktvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weighttvb now,tvbnow,bttvb* ?" L% Z$ @  s: B! y; x7 w
    then goto 2 - compare rest of(4)  - 2 with 2
0 u1 x# b' X" I4 j: v9 g8 t公仔箱論壇           if (left side is more weight)tvb now,tvbnow,bttvb! t: w% R7 e3 ?7 W! |
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer! d, C0 y  \5 ~# Z& W9 F4 c! p
          else ( right side is more weight)
6 l1 X# c/ p6 _; s, |5.39.217.77:8898              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
2 o9 u5 V! `8 y- J5.39.217.77:8898else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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