zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次公仔箱論壇: K5 t" o+ o/ \1 x
将比较重的那份再平均分成两份成一次
) X0 d; O( i& v5 R( u) h5.39.217.77:8898剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
  i9 i7 b/ ~, U# e: V公仔箱論壇if  (4v4)= same that means the rest of 4 is got more weight
9 D; B9 L8 R+ n. d3 q: z    then goto 2 - compare rest of(4)  - 2 with 2
8 P: B) M8 [+ @5 G2 `- |$ Q           if (left side is more weight)
2 \' ~* y9 F" d5 `. M9 I5.39.217.77:8898              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
0 c- W8 O) j3 ?3 s: m5.39.217.77:8898          else ( right side is more weight)
& w8 Y5 S( ?  S: U公仔箱論壇              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
: {: D" v  w# j% }3 x% E公仔箱論壇else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。