hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
1 k1 V8 J% f- q: Y1st u divide the ball into two group (i group 6 ball)
3 q6 Q2 N; r9 Y6 X7 {2 athen 称 them c which side is the heavy
) \! a5 H) J% `1 gthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 公仔箱論壇* s" c2 Z! f1 ^! v
if not balance take the heavy and then tvb now,tvbnow,bttvb- z7 |6 q- `6 z, S# M  v4 H
take the heavy group divided into 2 group i group contain 1 ball than 称 it / V% o" i6 y" D1 m
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
3 p7 g( p+ \; H' Y* G3 v0 D3 V（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
8 N+ e2 d/ W' V$ L& Q& P) V% W! }5.39.217.77:8898然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me