hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^6 V$ |& U) C$ `
1st u divide the ball into two group (i group 6 ball)
: x) d/ \3 A% p1 b, l' Q$ H( {then 称 them c which side is the heavy
  N( O7 i4 n# s5.39.217.77:8898then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
) X  }- j* R; [; t8 z; Y/ D5.39.217.77:8898if not balance take the heavy and then 5.39.217.77:88983 H( R1 g9 n) W/ ~4 J
take the heavy group divided into 2 group i group contain 1 ball than 称 it
. j, E8 z5 f. p. H/ y; W. Vthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
+ j$ ?$ a' p: }  \5.39.217.77:8898（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
$ G& F* U7 N6 a. n公仔箱論壇然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me