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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
- t8 D2 T/ B6 g6 |tvb now,tvbnow,bttvb共四堆
2 h# V3 X$ X# y1 z" O( V& o5.39.217.77:8898称两次得出异常的在那一堆,其轻重TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 h' X1 v- {7 k. H' u. q
在异常的那一堆中在称一次1 h( Q7 M0 w/ B  _
就可以找到了
divde the 12 balls into 3 sets of 4. * C& N: B- ]+ G, X
weight any 2 sets.
) ?* F( }9 ^1 m% X' L  A公仔箱論壇if the 2 sets are equal, then you know the heavy one is in the third
9 e7 ^) ~: C( c' q4 ^7 d; I+ c( qif one of the 2 is heavier, then the heavy one is in that set. v$ F) X0 X& H" t2 r8 r
then divide the 4 balls into 2.
& A7 f! X. W8 X, P. D/ K5 mweigh themtvb now,tvbnow,bttvb' O# ^, v0 ?7 y+ \) w
and divide the heavier into 1
$ I+ r+ d+ }% [" {  s- |5.39.217.77:8898and weight them.5.39.217.77:8898* s9 ?- A" Q6 C" H0 L
3 x weighing and get the ans.  
- Y- I" ]( P0 _* F- y0 B/ Z$ J' pin less than 15 secs.
1. 6 aside and weight.
9 {& K4 Q2 e! a9 l* V2 `; J+ xtvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.
  |( I: Y+ L, M, Y  f; s4 N3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
8 u# K6 k* U6 ]4 r. Q+ S! `( l, D+ O' b; I9 Q1 S9 M9 s  {
but i have a question. 重量異常 can be heavier or lighter.... so......
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