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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆公仔箱論壇- N/ e4 U# A2 }6 ~, [  Y3 J
共四堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。. B, P9 w: u; }8 H, `
称两次得出异常的在那一堆,其轻重TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: S1 D1 A3 x. U3 p
在异常的那一堆中在称一次
, L4 H* E; @. P& `5.39.217.77:8898就可以找到了
divde the 12 balls into 3 sets of 4. 6 B2 V# v: P2 ^( n: B9 z, s/ ?3 N* _
weight any 2 sets.
1 b2 F% `7 b+ q4 j$ ?) J5 |if the 2 sets are equal, then you know the heavy one is in the third! m0 S, M) h) m- r( h8 L4 \% j- g
if one of the 2 is heavier, then the heavy one is in that set
8 s3 @/ _6 x# t" g2 x( _% Xtvb now,tvbnow,bttvbthen divide the 4 balls into 2.' i& m) T: n% ^  V
weigh them' N! C2 e+ j9 z. p
and divide the heavier into 1公仔箱論壇9 T4 G! ^* q( w6 K+ ]
and weight them.5.39.217.77:8898# j9 e, E$ M0 k4 b8 d! j, A
3 x weighing and get the ans.  
$ G; f' z( [! c5.39.217.77:8898in less than 15 secs.
1. 6 aside and weight.5.39.217.77:8898. s, b) f6 \. Z' X
2. heavier side from (1), 3 aside weight again.
, A7 C' U) e8 l8 j4 p' Q- [% O9 }3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
9 A1 q" j! g3 B, o& N4 G$ q5.39.217.77:8898
) b4 _- W6 Z* f  kTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。but i have a question. 重量異常 can be heavier or lighter.... so......
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