zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
" @* ?7 H. Z2 }8 B5.39.217.77:8898将比较重的那份再平均分成两份成一次
9 K* q* Y& Z0 r  u9 L2 v% c1 Ztvb now,tvbnow,bttvb剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。8 `8 ]' ?1 J5 Q0 p* d( a
if  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇$ b+ p- U, E! a* R1 \
    then goto 2 - compare rest of(4)  - 2 with 2
/ K2 ?! I$ s$ d  U, ]: K/ F           if (left side is more weight)
1 `' O! q4 @9 u& W/ o5.39.217.77:8898              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb5 O9 @- V3 ~% h# V9 \
          else ( right side is more weight)
) }/ W2 w0 {% o5 s- l2 q5.39.217.77:8898              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
- g0 o4 ?" a, f9 q5 nelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。