Well..divided into 6/6 first to define a heavier group is certainly right. Randomly select 3/3 will result another heavier group. 8 }1 d! V$ k$ W, R% }$ f5.39.217.77:8898The problem is we don't know the weight of each individual ball, so it will not be accurate to figure out which ball is irregular by only weight them once. / m0 q3 \+ Y( ~. K; @7 l# H