i find one solution that is similar 4 C- j& |! M7 u: A' I3 Z: ?5.39.217.77:8898but i can't specify the heavier one is abnormal or the lighter one is abnormal when the case that has only two balls left.... ! x3 M5 V5 U9 e% C# B) l5.39.217.77:8898maybe there is a better one, let me see sin
actually this question always have someone asked, the calculation is very complicated, should give a no. of each ball, and first weight it in 6-6, and .... forgot...