That is a very simple mathematics question.
0 E8 [. I6 _) ILet x = Male, y = Female, z = Childtvb now,tvbnow,bttvb6 ^% U4 u9 B5 |0 }+ n& c0 H
6x + 3y + z/2 = 100 Formula 1 R6 H9 Q$ b& J( x$ a
x + y + z = 100 Formula 2tvb now,tvbnow,bttvb! X* L+ U& S9 H% }
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3! l3 Z# |; z( ^) R( c* P* w0 \
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
2 ]7 h* Q9 v+ q" W$ q! Y1 v5.39.217.77:8898Formula 4 can change into 11x + 5y = 100 Formula 5
+ A/ D% {2 p! o4 C公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% m- H4 P' |7 ]9 W6 r" g% R
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
5 ^8 y9 u+ U1 ?6 [公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |