That is a very simple mathematics question.2 O2 Q9 @! Y8 G4 k$ ? n
Let x = Male, y = Female, z = Child
6 ^1 G5 v f3 P% w- |6x + 3y + z/2 = 100 Formula 1
' ], v- c3 X6 l! E) cx + y + z = 100 Formula 2
6 B8 N& F; R6 `8 o4 Otvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3& [1 y' J v, _, D1 m4 Y9 [: ]2 W9 F
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4% w+ j M8 u- A4 l( |: D6 ~
Formula 4 can change into 11x + 5y = 100 Formula 5
1 B, ]' Y9 `7 ]' h" c. n' t5.39.217.77:8898In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.7 J1 D0 D0 r- p1 q2 U1 l
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
8 B8 n: i# K3 C9 _公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |