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[IQ題] 一道真正難倒億人的智力題

一道真正難倒億人的智力題) u2 H! \8 [$ m* s

4 ]- }1 ?1 {) k) g# o, ^4 E* K公仔箱論壇
& E/ `1 V4 O" o2 _# }7 z公仔箱論壇5個囚犯,分別按1-5號 在裝有100顆綠豆的麻袋抓綠豆,規定每人至少抓一顆,而抓得最多和最少的人將被處死,而且,他們之間不能交流,但在抓的時候,可以摸出剩下的豆子數。問他們中誰的存活幾率最大??tvb now,tvbnow,bttvb- K( _3 O& E6 J2 w& V
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提示:公仔箱論壇; V& a# D/ {& f, }4 a
1,他們都是很聰明的人;tvb now,tvbnow,bttvb  k6 p0 v1 Q8 P  A& F# s/ H
2,他們的原則是先求保命,再去多殺人;6 K) t# }4 f# I8 h  n
3,100顆不必都分完;
* `) s* Y! i; G; Q) H4,若有重復的情況,則也算最大或最小,一併處死;
5 m0 A' u2 h  @+ V4 d. k$ t1 R公仔箱論壇: F' |: d4 R3 m+ K0 O8 B, `
5.39.217.77:88987 u" U  v9 u# o; y$ M& I- O0 W1 H
答案晚點公佈
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. R' u% G7 K' g" Z  Ftvb now,tvbnow,bttvb% S7 L5 Y/ q! c' X

9 |$ b$ a( s' \) a0 etvb now,tvbnow,bttvb, i1 d$ K2 H+ v' K- {
答案:結果是只可能大家一起死。無論怎麼拿1號都是死的,所以怎麼樣他都得拖人下水,1號會拿20個,結果是前4個都拿20個,最後一個拿幾個都一樣,大家一起死。
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* ?3 g+ y9 M' u[ 本帖最後由 蘭昀 於 2007-3-7 05:11 PM 編輯 ]

err

no.2? cos he can counts how many no1 took from the bag....only a quick guess

sorry forgot explain

if no1 took 50, the bag left 50, then no 2 takes 25 the must be in between, if no1 took 30, bag the bag left 70, take 29...etc,
da answer is NO.5 coz he don't hv to do anything n da first 4 people is die already...................
Don't kow
they will all die becuz they will each get 20
真係好難
>:D< 開估啦 !
NO.1 ,NO3 AND NO4
有难度,慢慢想
why
好好想想!
I had a quick guess, is No.1. 5.39.217.77:8898- w1 d1 J8 s. G0 M. W6 Z
Because what ever he or she taken, the next person will take what ever had taken with +1 or -1 to ensure they havn't got the same number. at the end, no1 will had the most likely middle number and without a same number. of coz he will need to pick a number from 3 to 19.
i don't know
看来我的智商确实比较低,乖乖的等答案吧! :'(
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