That is a very simple mathematics question.5.39.217.77:88988 z1 N9 j; y7 \ E. e' j
Let x = Male, y = Female, z = Child% o r3 i' b, R5 M, e, O& A& c) A
6x + 3y + z/2 = 100 Formula 1* i* n( t5 P" S) Y- u z
x + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 j0 U3 b% W, W8 N8 ?$ [2 d
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇3 }# l' P6 Y$ @8 A' n g3 a
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 47 A5 h }' P3 `( o* F
Formula 4 can change into 11x + 5y = 100 Formula 55 J' ~0 e7 b0 T' o! |* ?8 O- ?
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.' P/ x$ C3 b& h3 H6 [ Y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
+ ]4 j1 p& s1 v( E7 d3 ?tvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male. |