put six on each side first5.39.217.77:8898$ ~+ Z( ~2 Y0 R8 l
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from the heavier six, split it to three on each side5.39.217.77:8898& z# U& G: Y" g$ e6 ]6 `
7 | K$ c: ~. g+ q# l! ~ atvb now,tvbnow,bttvbthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |