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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
* ^# s# N6 e3 G% V1 O+ s2 M; ytvb now,tvbnow,bttvb共四堆
# u2 E. Z# z. {( Y* x$ R公仔箱論壇称两次得出异常的在那一堆,其轻重
: r6 v( J4 k$ E) _( h0 M; |在异常的那一堆中在称一次* N" G& e* b0 v' n+ d/ e& e
就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb; M' l  D, N$ ?/ T
weight any 2 sets.
9 G. j0 g3 a3 i- V5.39.217.77:8898if the 2 sets are equal, then you know the heavy one is in the thirdTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。; z$ f+ m& K. H: a8 Y
if one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ a0 b4 ]: _- B" A9 @. u/ ]. n
then divide the 4 balls into 2.# u/ E9 X. T2 G' V0 k
weigh them
( I3 N8 h4 A: B$ @0 J1 S; g! u3 rtvb now,tvbnow,bttvband divide the heavier into 1
7 o+ i- q, a# ?9 U. vTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。and weight them.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。* J! {9 Y' U0 o" \3 y! \+ O+ h
3 x weighing and get the ans.  
8 T3 o+ N. Q2 j* d/ p/ w8 yin less than 15 secs.
1. 6 aside and weight.公仔箱論壇- f4 G  b# R, ~6 t
2. heavier side from (1), 3 aside weight again.; [1 r+ S" Z4 d' u( i5 d; U( f1 h
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.77:88980 @, T* Y. N2 {: S0 n( E" |% Q
7 `7 U* k( y. s5 y& c1 G$ n, j
but i have a question. 重量異常 can be heavier or lighter.... so......
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