1 - compare 4 with 4
3 {1 z J* S) m6 Stvb now,tvbnow,bttvbif (4v4)= same that means the rest of 4 is got more weight5.39.217.77:8898+ k5 l/ T, U$ x- x# Z/ _5 K
then goto 2 - compare rest of(4) - 2 with 2 5.39.217.77:8898$ X2 L$ P' H$ W1 m+ F, _+ K7 {
if (left side is more weight)
: C `, a) n: y1 @5 b" x5 s( `7 g5.39.217.77:8898 then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb* i) ~4 F3 |5 m/ o
else ( right side is more weight)5.39.217.77:8898- ]1 L* O4 k. @0 A G
then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvb now,tvbnow,bttvb1 `0 Q9 N. o8 Q- X1 }
else ( the left 4) then compare with above , or right 4 also can compare above method... |
發表於 2010-9-21 10:33 PM
| 
