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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。0 M* d& W3 y, o& m& D2 A
将比较重的那份再平均分成两份成一次
& p. ^2 _" M' ]/ n5.39.217.77:8898剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
( X1 k9 e- E) t, W2 M4 o' \公仔箱論壇if  (4v4)= same that means the rest of 4 is got more weight
! d" \/ e4 k- T% d公仔箱論壇    then goto 2 - compare rest of(4)  - 2 with 2 ! m0 v8 k& ]4 q3 |7 I2 Q
           if (left side is more weight)( I! H, v; J: |1 a. U
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer5.39.217.77:8898: ]& V4 N% `1 F8 J9 ^
          else ( right side is more weight)
7 D* M7 O* m  `% V% \tvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
# x9 `& `9 S  U, d6 O: v公仔箱論壇else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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