zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
% ]3 {! ]; c5 J; c将比较重的那份再平均分成两份成一次( ^5 X/ Z. b' X
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4公仔箱論壇6 W4 U  H+ A0 g2 G1 Y
if  (4v4)= same that means the rest of 4 is got more weight
! m7 z' L) ?, U! x: ^9 r    then goto 2 - compare rest of(4)  - 2 with 2
7 P6 N7 W, k2 e- Z4 j( F2 F           if (left side is more weight)
$ j- J+ J+ z) f6 r5.39.217.77:8898              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
3 _! g9 t1 D5 ~7 a5 J% E- G5.39.217.77:8898          else ( right side is more weight)3 p  I% [/ y' V. p. `$ x
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer/ n! u2 ]4 Q, j. c3 o
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。