1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 1237 p4 Z# V7 C1 H
For 111 would be 1x1+1=2 that is 2 times of 3rd 1 ( \- Y0 f# ]0 P9 [3 V公仔箱論壇For 123 . Q( x$ @1 P5 Z% S6 f% Z$ h/ P! Htvb now,tvbnow,bttvb1x2+1=3 that is 1 time of 3 6 @' s% r+ d' [* E5.39.217.77:88981x3+1=4 that is 2 times of 2. L7 q0 Z* G5 U3 H
2x3+1=7 thta is 7 times of 1