The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
8 ]$ `/ f e5 t$ w3 I5.39.217.77:8898
, @, l) Y1 H; ~9 q8 U6 y [& _( Z8 ~tvb now,tvbnow,bttvbStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. 5 u6 x* j% T: d' v( m- g3 X5 }! F
% |2 I0 x+ }! g$ pNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
: N o% m1 Q8 v+ q' ?. L+ L* v公仔箱論壇6 L! V: D/ c0 A/ V! @, z" {
#3 did the obvious choice 40 divided by 2 =20, so he picked 20TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。% M, [% j" B1 ?- j: o; ?
. S# L5 s4 H8 r' K; T1 M" A6 ^TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.# M/ c- b7 z& h1 Y
( q8 {, G5 ]8 E/ O; \- F, O9 r公仔箱論壇#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.( V, b2 F0 J1 w: g8 a$ x# f" F$ m T
, p" M6 X1 q1 D, Y( O4 tTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
