lux1261

答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1

lesley

^:)^ >:D<

leekh

thx

jc49

let cc

Special_Forces

not possible

sm911118

不知道要怎麼做阿??

laou

hao

jen198053

there got more simple way to do it, just read my way, the one i answered before

samkk123

the

hakis

see 了

jenfien

第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了

fxenon

how?

nyb

先分3个一堆
5 U& r% ]- {  u共四堆
! b9 ~6 w( M0 v( T1 [公仔箱論壇称两次得出异常的在那一堆，其轻重
- Z8 S9 V3 y6 l5 g; G/ ]6 [$ i5.39.217.77:8898在异常的那一堆中在称一次
5 r5 S4 `* f0 i9 q6 f7 S/ k7 q公仔箱論壇就可以找到了

ceteriz

divde the 12 balls into 3 sets of 4.
  u0 O2 o* p& ]weight any 2 sets.tvb now,tvbnow,bttvb* e: k2 t$ K: L, G8 l
if the 2 sets are equal, then you know the heavy one is in the third
5 f* X8 v+ A9 S0 \! R公仔箱論壇if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇) r6 ?2 S5 A3 N0 E2 c4 a9 I8 K/ k
then divide the 4 balls into 2.
1 U+ S1 x# k! ]0 T( Aweigh them
: Y) [. t- V& S8 ]3 R7 N; w5.39.217.77:8898and divide the heavier into 1- V1 ]# }# v1 s  R) }7 v
and weight them.
4 }1 i5 T% Z9 w; J! V, B3 x weighing and get the ans.  
% S! x6 a: ?( O, q公仔箱論壇in less than 15 secs.

kino_kino

1. 6 aside and weight.
  i! i5 ^! E2 Z8 N' \! R% a6 C4 Ytvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.公仔箱論壇- Y$ T2 {, T8 a+ u0 z; n
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
4 u8 w7 `, n5 x  j: S3 r, l; u, {0 R' d
but i have a question. 重量異常 can be heavier or lighter.... so......