divide 12 into 6 one side n balance it..
8 `8 g. V' N$ u. h( }- f3 ?0 ?: ^den take da heavier side which is 6 n divide into 2 parts again..5.39.217.77:8898! |. R8 _& ^3 l3 U6 ~, {
3 one side n another 3 another side..
0 B. C3 S6 ~5 F& Rden u take da heavier part again..5 f+ _$ F9 i) f
now u left 3 pingpong.. u can simply choose 2 of it n balance again..5.39.217.77:88980 q S+ W0 @' @9 N- r1 I6 `4 F
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan |