take out 10 balls and 5 in each side
; D. v' [: h, n; @1 u, m% v/ m; s- Mif both side balance mean the other 2 balls one of them must be the heavy one then just take them to weight will find out which one is heavier.) P# c! B. y) g: i, ]
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if the heavy ball is inside the 10 balls, take out 4 balls from the heavier side which had 5 balls to weight 2 balls in each side.
. X2 {$ I7 N) t4 Z* ]5.39.217.77:8898if both side balance, which mean the one left is heavy one if not, just take the heavier side to weight will find out which one is the heaviest one.
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used less then 1 min to find out the answer.... |
發表於 2007-12-31 05:47 AM
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發表於 2008-1-1 08:48 AM
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