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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb& {! d/ @/ ?  {6 }& q& ]
1st u divide the ball into two group (i group 6 ball)
7 O" S* ~! ~/ z! v9 ~  N5.39.217.77:8898then 称 them c which side is the heavy
  h$ O% D& f# t6 F7 _6 ~9 Cthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 公仔箱論壇# l* E" D: T' F; u% A( {
if not balance take the heavy and then
" @6 ?8 ]" u- u6 o# X: D' w  p) D公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it
# A$ R4 _( W; @8 `5.39.217.77:8898than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: . L8 ~0 T! C$ E8 V% k- G
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边) V$ l0 X' J3 c
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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