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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^5.39.217.77:8898. F$ I" u: Y' _) v
1st u divide the ball into two group (i group 6 ball)5.39.217.77:8898: O+ g" e8 |3 r4 s, u
then 称 them c which side is the heavy
: n/ e! s+ p0 }7 l( {. k5 l5.39.217.77:8898then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
$ ?/ D1 i+ X2 ]& G& I公仔箱論壇if not balance take the heavy and then 公仔箱論壇3 h& K) t% x" s: I$ H9 C* w
take the heavy group divided into 2 group i group contain 1 ball than 称 it , c! A) e, k, S1 n% Y4 y+ f
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 y/ y! G% z6 L1 p6 r
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边公仔箱論壇: Y/ ^2 ]9 L) e
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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