put six on each side first5.39.217.77:88984 O$ h |9 i4 U- X9 K4 z
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from the heavier six, split it to three on each side
* L# t. m( x' @5.39.217.77:88983 \/ G# i1 _4 U9 |4 M' F: |: m
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |