let the 12 balls be numbered 1,2,3,4,5,...,120 k, ^( Y# M1 H) N U
weight 1234 with 5678
1 |7 r: k7 b1 o0 L6 \case 1
, x( [( I& V- L2 q: m; }if 1234>5678, then weight 125 with 678# h/ _, e: H! Q) a/ N
if 125>678, then weight 1 with 21 S# s# j" L; G; G. {
if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2
$ k ]% t. e/ t9 Y3 _+ Q- Pif 125=678, then weight 3 with 9
! k) O: w% I: O5 @' j9 H1 q& p5.39.217.77:8898if 3=9 it is 4, else it is 3
3 ~6 B+ b, S+ C& l7 t( `if 125<678, then ewight 3 with 45.39.217.77:88981 U! v3 S0 j. {
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4
" e1 u Q' b* ?& [! V# ^
& Z3 i# O2 m- f, V& Q( p2 A, |0 K" scase 2
8 Q3 F/ g. D! ?. ~公仔箱論壇repeat above for 5678 instead of 1234 if 1234<56782 w4 a* z' k2 b: d
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case 35.39.217.77:8898: I" e! z- i3 q" o
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain公仔箱論壇# d0 h' u& L: r
# u5 k! [4 j; F- j3 rtvb now,tvbnow,bttvb[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ] |
發表於 2007-5-7 11:25 AM
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太简单了吧？