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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
" x# h/ G: J3 |% P$ w  O共四堆7 k) p1 x( @- @
称两次得出异常的在那一堆,其轻重
/ Y* h8 H$ e/ w: u5.39.217.77:8898在异常的那一堆中在称一次
3 Q8 E! f: h& s" S8 j就可以找到了
divde the 12 balls into 3 sets of 4.
5 U! b+ L4 Z( h: q2 w" @0 ~. c5 MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.
3 D, V; X) D6 f. b  O3 eif the 2 sets are equal, then you know the heavy one is in the third
9 ^/ F0 \( ]$ g/ t4 Lif one of the 2 is heavier, then the heavy one is in that set
' q  I0 O4 ]( \! \: L6 r1 Lthen divide the 4 balls into 2./ H) e% L6 C# W* |1 a& a
weigh themTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ g; R' T, v! X9 z0 L
and divide the heavier into 1tvb now,tvbnow,bttvb! n2 r) c  c- d: T' Z) u5 T- P: |5 S
and weight them., b7 r( ~9 |; g: H
3 x weighing and get the ans.  
' W2 y5 j+ I( Z& ftvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.公仔箱論壇& Z' p3 W# b- K4 J/ ]
2. heavier side from (1), 3 aside weight again.
- p* w1 l2 J) Ntvb now,tvbnow,bttvb3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. ' w- J) s% d3 M& n# l/ R  j
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。! ~5 O% z) G$ g$ y9 g
but i have a question. 重量異常 can be heavier or lighter.... so......
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