zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次! C5 P3 ]. ]3 ~% V3 C/ ^2 Z* O
将比较重的那份再平均分成两份成一次5.39.217.77:88984 ~8 ^7 f9 j% k
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4. T( f7 w* K' u# ?, F  ~
if  (4v4)= same that means the rest of 4 is got more weight
1 j1 a; g7 ^% o7 E- v    then goto 2 - compare rest of(4)  - 2 with 2 TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。# K% l. g4 h  K. a/ R
           if (left side is more weight)
# Z1 R3 d! D' N& g( [/ q; R/ R              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
2 ], V- d3 X2 K+ o3 }$ F          else ( right side is more weight)
" M' r7 n( i1 F% o! w' s+ X9 ^              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.77:8898/ v% p) l% b& f+ t, Z0 R
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。