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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^/ r5 V8 B; t2 e
1st u divide the ball into two group (i group 6 ball)5.39.217.77:8898, T" h5 f  q/ _' h2 O
then 称 them c which side is the heavy
1 O( L) a) F( {5 V+ o: S9 a公仔箱論壇then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
4 z1 ?! j8 \; T  D7 O5 G5.39.217.77:8898if not balance take the heavy and then tvb now,tvbnow,bttvb  x( W2 h$ A3 k) B
take the heavy group divided into 2 group i group contain 1 ball than 称 it
* G* y$ X' H# |( t+ `0 N/ G  G0 b( Q! D公仔箱論壇than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 8 W- a/ t( O% m: |5 u9 H( f4 b) u
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
- t1 Q; i! g2 Q% ntvb now,tvbnow,bttvb然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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