hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
; F* R1 v2 r7 o5.39.217.77:88981st u divide the ball into two group (i group 6 ball)公仔箱論壇: F7 p: n" m* ^. n- c6 J
then 称 them c which side is the heavy 公仔箱論壇2 Q) T) d6 K/ F3 R6 n7 F8 N. M3 N2 Q
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
* H  n9 V6 H+ H; ^+ q+ Hif not balance take the heavy and then 公仔箱論壇  p6 X: t1 W7 k
take the heavy group divided into 2 group i group contain 1 ball than 称 it
) f/ s, X6 f" `; u8 v5 }! xtvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
- {" |1 w8 B! s5 o+ vtvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边公仔箱論壇' i9 f' a8 S/ _: i) ^* H1 M% d
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me