hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
" R" V4 g# Q2 `1st u divide the ball into two group (i group 6 ball)
  G) O5 T/ Z2 q5.39.217.77:8898then 称 them c which side is the heavy 1 G) _5 ]/ z; ], t8 v# \; V' C
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group ! p  s- H$ S3 F8 Q: u" W# P& c* b/ {
if not balance take the heavy and then 5.39.217.77:88981 I7 {5 p, R' _6 a
take the heavy group divided into 2 group i group contain 1 ball than 称 it
, e, y0 c6 |, G4 r  J5.39.217.77:8898than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。8 {3 b/ T  D! e9 n" ~) s) l
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边# u" T8 m( Y( _" H' T
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me