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easy, one minutes i solve the problemtvb now,tvbnow,bttvb. o) n2 g* D# p, M
divide into half, mean 6/ 6
' U6 m5 l5 V, ~0 W3 ltake the heavier 6 ping pong$ \  P$ W+ s; `0 q- d1 [: Q+ p
divide into 3/3, take the heavier 3tvb now,tvbnow,bttvb" K7 M' H4 x7 ?7 N
take the the other 3 that have the equal weight, switch each to measure, the most important things is labeling the ping pong so that we can recognize
量3 次, 一次 6比6, 一次3比3, 一次1比1, 就可以找出来了
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