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easy, one minutes i solve the problem4 R5 Q7 |' j- R) D( x% K4 {* [
divide into half, mean 6/ 6
) s( M( x1 L1 |0 J. x公仔箱論壇take the heavier 6 ping pong
0 C4 {" A: b! G, `" gtvb now,tvbnow,bttvbdivide into 3/3, take the heavier 3
/ V( ^; e+ ?: k公仔箱論壇take the the other 3 that have the equal weight, switch each to measure, the most important things is labeling the ping pong so that we can recognize
量3 次, 一次 6比6, 一次3比3, 一次1比1, 就可以找出来了
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