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easy, one minutes i solve the problem
+ e0 V# ?2 A. Ttvb now,tvbnow,bttvbdivide into half, mean 6/ 6
* n$ \: i  J/ S, G* ]# m4 I# }+ etake the heavier 6 ping pong
! n1 G' s% ?) k6 ^1 j) jtvb now,tvbnow,bttvbdivide into 3/3, take the heavier 3
9 T( [5 E- z2 _8 d$ b5 ^2 z8 f5.39.217.77:8898take the the other 3 that have the equal weight, switch each to measure, the most important things is labeling the ping pong so that we can recognize
量3 次, 一次 6比6, 一次3比3, 一次1比1, 就可以找出来了
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