jacky101mm

Well..divided into 6/6 first to define a heavier group is certainly right. Randomly select 3/3 will result another heavier group.
1 r- V0 \* ]9 o1 \9 {6 e4 }5 IThe problem is we don't know the weight of each individual ball, so it will not be accurate to figure out which ball is irregular by only weight them once.tvb now,tvbnow,bttvb6 s# [1 x# M9 ~" p% O, t