tcmhw

divide 12 into 6 one side n balance it..
0 {+ I/ ?, f  R- r/ F; [5 q5.39.217.77:8898den take da heavier side which is 6 n divide into 2 parts again..
- V4 `. g2 a* K& d3 one side n another 3 another side..
- D# j5 c- e# K8 f$ Rden u take da heavier part again..
- k+ ^: x/ \/ j$ @& m5.39.217.77:8898now u left 3 pingpong.. u can simply choose 2 of it n balance again..公仔箱論壇0 ]0 Z: i& I6 `8 ?
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan