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回復 #1 MagicAndy 的帖子

divide 12 into 6 one side n balance it..
6 Q7 A) {$ D2 s, E% x7 D( I5.39.217.77:8898den take da heavier side which is 6 n divide into 2 parts again..
5 E' h. F! C/ M4 @1 o9 P; j( ]; |; v9 Mtvb now,tvbnow,bttvb3 one side n another 3 another side..
  g4 j' S* r7 W0 Gtvb now,tvbnow,bttvbden u take da heavier part again..
+ u' P% Q3 R3 K) j7 T* s, `) q5.39.217.77:8898now u left 3 pingpong.. u can simply choose 2 of it n balance again..
3 k2 d3 z  [$ b/ U  ~% W$ h& V5.39.217.77:8898if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan
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