There is 12 balls.. divide them into piles of 45.39.217.77:8898' T7 I. v* o9 }7 K
so 3 groups for 4..name is A,B,C* v- T K5 x, ?9 H2 ]
case 1:
r" Z8 A/ b" c, n8 Zmeasure A -- B 公仔箱論壇# V3 o, l S+ O8 X5 z6 U
A or B is heavier 5.39.217.77:8898" A S9 J$ g. A! ]6 {
divide that group into 2 by 2
! ^% y" i0 Q- b: i; t* @then divide heavier group into 1 by 1
K4 x& l" \4 j4 G( _tvb now,tvbnow,bttvb, I! `; ~) m7 }' v% {
case 2:* a+ o6 C9 y4 w" W) C1 T
A and B is the same.. therefore C has the heavier balltvb now,tvbnow,bttvb; D7 [' Z' Y% d; a" ?4 Z* `) ~9 ?
divide C into 2 by 25.39.217.77:8898$ B8 f' J; v) g/ e' Q! E2 ^' u
then divide heavier group into 1 by 1..' U0 F2 S, D( P% c. {8 V2 @# @
! M: y) T4 }2 ugot it in 30 seconds.. not so hard -.-' |
發表於 2006-12-8 01:06 PM
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