put six on each side first
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9 }( @. f7 ]. x7 h5.39.217.77:8898from the heavier six, split it to three on each sidetvb now,tvbnow,bttvb& B% d9 P- V7 C( ~" `6 d: H
- m" ~4 a1 ~/ m/ ?( q6 o( Tthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |