sky888

put six on each side first. Y/ f% E: M4 a/ o( V" I
tvb now,tvbnow,bttvb+ @* ~: s$ i1 H. r( b: N% F+ w
from the heavier six, split it to three on each side
% R, `* O) ~' R* j9 }* A
. a0 Z& |1 M/ ^, othen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one