put six on each side first
6 {+ y) n9 s9 R- W; K& w5.39.217.77:8898
# |( r4 U! F( D8 d8 N. ftvb now,tvbnow,bttvbfrom the heavier six, split it to three on each side5.39.217.77:8898- i9 f5 G" V7 b7 D, O3 d* e: u
( l$ Q) s) _/ j2 b' T) [$ H5.39.217.77:8898then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |