twinsdragon

That is a very simple mathematics question.
2 m4 m0 b' J% FTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。4 k* g8 ^0 a, P3 k- l- A# v7 o
6x + 3y + z/2 = 100   Formula 1
- _4 l6 l" ~6 o6 }x + y + z = 100    Formula 2
& L# b( p+ A# D: cSimplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.77:88982 B4 c! s( z  r/ x# u/ C
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 43 [' I* r3 O" }% h6 R* C1 _5 x
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.77:88983 r8 o7 N0 u* @+ \
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
2 E3 q1 \+ K4 q' C/ Y$ LAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。. d) {3 n+ m% O5 e
Eventually, the answer is 20 female and 80 children and no male.