twinsdragon

That is a very simple mathematics question.tvb now,tvbnow,bttvb" {5 b: R" `* ?
Let x = Male, y = Female, z = Child0 T! ?( T3 J; l4 {0 z
6x + 3y + z/2 = 100   Formula 1
; y  Z9 v  ]1 x& j4 f8 i6 s5.39.217.77:8898x + y + z = 100    Formula 2
0 y( F! i  X& R! A1 C' ESimplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇. r# }& Q$ g5 v8 M3 [
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
+ q3 L/ E; g. L. x4 `" Q% J# D( B( `Formula 4 can change into 11x + 5y = 100 Formula 5
5 ?; d" M- c5 O( d6 P3 DIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
4 L% |# A: y; x( [  K9 r& E( pAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇9 p- B5 T, i5 D5 i
Eventually, the answer is 20 female and 80 children and no male.