twinsdragon

That is a very simple mathematics question.+ p1 \4 J! J/ v
Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb' n6 x( C/ a0 N$ g
6x + 3y + z/2 = 100   Formula 1
5 M1 s$ M9 `8 `! {# v# r9 Mtvb now,tvbnow,bttvbx + y + z = 100    Formula 2
# n  @: y2 h' [' xSimplify Formula 2 into z, we get z = 100 - x - y Formula 3* d8 I5 a; C* V% Z8 i
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
, p6 E, X/ ^* a9 g0 MFormula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇; R" X9 S' t% }& Q
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.77:8898) i9 W' K' @8 A8 [. r7 |
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
0 i& Q7 d( n0 Q, b公仔箱論壇Eventually, the answer is 20 female and 80 children and no male.