twinsdragon

That is a very simple mathematics question.
) b8 k/ L' D* p3 L4 g% bLet x = Male, y = Female, z = Child公仔箱論壇  u1 z0 |$ g: S6 s; {# s) G2 i
6x + 3y + z/2 = 100   Formula 1
; D3 \# w$ T' i9 h7 a% O" A( v  Fx + y + z = 100    Formula 2
1 ]- @' c* P! O& x- N! h+ I' M公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
5 }8 m* [* M/ i+ o, [- FSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
: \7 E( f: `# _# Q2 g/ [% AFormula 4 can change into 11x + 5y = 100 Formula 5
/ V, P" C% G" n/ P8 V+ i$ {TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
5 f6 i6 r& b" }: e  w9 T公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
( x2 J4 G# s; N1 |; @1 s( F/ H* gEventually, the answer is 20 female and 80 children and no male.