twinsdragon

That is a very simple mathematics question.
* C) t& L: D$ w) f) q3 ?3 w0 R公仔箱論壇Let x = Male, y = Female, z = Child公仔箱論壇" f! X$ N2 r8 p) q
6x + 3y + z/2 = 100   Formula 1
2 c' ~* g, U+ O1 j& D$ OTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。x + y + z = 100    Formula 2TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。- W$ c7 f& [# c* t) C2 \0 t
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
: g$ [- s- L7 {5.39.217.77:8898Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇5 a  \0 h- x% A/ ~
Formula 4 can change into 11x + 5y = 100 Formula 52 i) C: n& [6 {- r( {* P1 e8 E
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。7 v  T  e2 v1 }$ O; {4 |( \$ W
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.' y7 A; j0 _. r0 d% o- t, D
Eventually, the answer is 20 female and 80 children and no male.