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The numbers in this series describe how the previous number is formed.
  b2 ^. F! A6 N% `- @* Z- H, w3 ktvb now,tvbnow,bttvb5.39.217.77:88986 ]; O+ p6 Q. y$ Q: G3 F# y
The first no. is 1
% n% I1 x9 |( G$ w' d0 @5.39.217.77:8898The  next one describe it: there is only one "1", therefore 115.39.217.77:8898% L- n1 x/ i) y& Q0 f
The next one describe the "11" as there are two "1", therefore 21
8 y& e  S6 k/ Q+ `5.39.217.77:8898The next one describe the "21" as there are one "2" and one "1", therefore 1211
; m* W# G$ P  q; F: I5 KTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。The next one describe the "1211" as there are one "1", one "2" and two "1", so 1112215.39.217.77:88981 ?2 f* G( a; g4 d& d
The next one describe this "111221" is three "1", two "2" and one "1" so the answer is:5.39.217.77:8898* P! x3 h) L8 D
312211
. b0 x0 F0 ?+ n: k5 Z5.39.217.77:8898tvb now,tvbnow,bttvb$ x4 C' h3 D  R9 m
I give up on question two.
本帖最後由 gm3stevens 於 2012-6-23 06:56 PM 編輯
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After seeing the IQ question 據說這是蘋果公司的面試題, it reminds me of grouping the left hand side numbers to reflect the number on the right.
5 f0 d5 c- p2 ^4 \! X$ `tvb now,tvbnow,bttvb公仔箱論壇" b: I! W: R7 c9 D  V# P
So the right hand side number 0 can be represented by number 1 0 {+ E, j# g9 r9 i3 w! P) U  \
The right hand side number 1 can be represented by 3,1,2,9,7,5
1 y# m& p  B. s+ H$ s5.39.217.77:8898The right hand side number 2 can be represented by 2,5,8,1,6,7,3,0
7 ]$ G9 i* a  w5 J0 `The right hand side number 3 can be represented by 5,9,8,3tvb now,tvbnow,bttvb3 L! n+ ~1 n/ t0 \( {+ P
The right hand side number 4 can be represented by 6公仔箱論壇) Q( C! f0 R5 ~1 f: `
Now the question is 8136, check the above list, 8,1,3,6 are grouped under 2. Therefore, the answer is 2
( z% B$ q4 H4 ^0 ]/ z+ s5.39.217.77:8898
  y- H2 P* A0 c; c3 e6 mtvb now,tvbnow,bttvbSorry. My bad. Someone told me that it is actually counting the number of holes in the given number.
6 V3 v5 L/ g, w  [( i- M- W. G' hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。There are 3 holes in 8136, two from number 8 and one from number 6 so the answer is 3.
$ i/ L- }2 i# Z( U5.39.217.77:8898
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