gm3stevens

The numbers in this series describe how the previous number is formed.公仔箱論壇! w; z7 {( a  |% Z2 A0 A3 X) I

  q$ n; M* m0 v' a8 K8 o4 qtvb now,tvbnow,bttvbThe first no. is 1TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。# ?6 W( X2 O% O- D
The  next one describe it: there is only one "1", therefore 11
9 a; T, E7 B+ N, h) x' ZThe next one describe the "11" as there are two "1", therefore 215.39.217.77:8898" I8 G) t, T4 C7 ^4 E# x
The next one describe the "21" as there are one "2" and one "1", therefore 12116 R) l! A7 F" @# V. O( q
The next one describe the "1211" as there are one "1", one "2" and two "1", so 111221
8 w: g( ^0 h- u! f. htvb now,tvbnow,bttvbThe next one describe this "111221" is three "1", two "2" and one "1" so the answer is:
8 u; _3 O9 O$ C7 Z" T0 C) L  U312211' f- Y3 F! O! m4 y1 W5 |4 P
tvb now,tvbnow,bttvb( J6 \& w/ g3 u$ `1 `
I give up on question two.

gm3stevens

公仔箱論壇% @$ z$ P& |4 S

3 L2 m/ m8 S& R4 N- p. b  l公仔箱論壇After seeing the IQ question 據說這是蘋果公司的面試題, it reminds me of grouping the left hand side numbers to reflect the number on the right.
, @- N9 y7 p9 T% m2 X9 ?tvb now,tvbnow,bttvb+ y' R& F* ~: d
So the right hand side number 0 can be represented by number 1
, u4 k5 p  @0 ^- t/ I! Y# `1 Htvb now,tvbnow,bttvbThe right hand side number 1 can be represented by 3,1,2,9,7,5
% S+ Q0 e) j8 c- }% A$ H0 etvb now,tvbnow,bttvbThe right hand side number 2 can be represented by 2,5,8,1,6,7,3,02 V1 @& {2 ^1 R( H+ B  ^
The right hand side number 3 can be represented by 5,9,8,3公仔箱論壇$ Z# G: b% |3 q0 h
The right hand side number 4 can be represented by 6tvb now,tvbnow,bttvb& }) K; p* r; ~
Now the question is 8136, check the above list, 8,1,3,6 are grouped under 2. Therefore, the answer is 25.39.217.77:8898  ?* v# r( G8 o

0 E2 e- X4 M3 Y/ }4 Z. TSorry. My bad. Someone told me that it is actually counting the number of holes in the given number. , @% E& w! J; G2 [' \) b& m  \  O
There are 3 holes in 8136, two from number 8 and one from number 6 so the answer is 3.tvb now,tvbnow,bttvb( q) }' T5 h" B" s4 O
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