number 4 has the best chance to live
& m/ D+ p, O6 P; {7 v1 k x- UTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。assume number 1, 2, 3 and 4, pick number a, b, c and d.
( J I" Z8 e% y; U- K' F1 {tvb now,tvbnow,bttvbnumber 4 knows how many left in the bag which is 100-a-b-c: m8 F2 i& s: H6 e$ H, j: Q8 r) }
take the average of (100-a-b-c)TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。& N# m6 F/ w$ O( |) [$ {1 u
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)4 o2 g( z8 n* a* [! G
and number 4 can squeeze himself into the average and what number 5 picks.
/ V& |2 t+ Q1 p$ v( j4 Xtvb now,tvbnow,bttvbso number 4 will have the best chance.
! M/ T) a2 g% a) g: ]TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
. f) I( R/ ?( H5.39.217.77:8898i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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