number 4 has the best chance to live
; g/ s+ P4 D9 |5.39.217.77:8898assume number 1, 2, 3 and 4, pick number a, b, c and d.tvb now,tvbnow,bttvb- b0 C! E1 Z5 x( B0 {$ l- J
number 4 knows how many left in the bag which is 100-a-b-c
* Z/ P, ]' J6 G! R( y: ytake the average of (100-a-b-c)
2 q' a1 N) y) }* r; b3 }! Wthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)5.39.217.77:88988 E0 S. P' E- d
and number 4 can squeeze himself into the average and what number 5 picks.
! z& H! ?( i6 l- g: I0 @tvb now,tvbnow,bttvbso number 4 will have the best chance.
9 m; x. x* H6 A- H( H* k7 M公仔箱論壇
0 G5 U$ p2 O) w* i4 j% Bi hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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