number 4 has the best chance to livetvb now,tvbnow,bttvb0 S G8 h, x! m' u6 y1 o+ @# m
assume number 1, 2, 3 and 4, pick number a, b, c and d.0 u+ u* W, @$ C1 j; \( N& U" k) G
number 4 knows how many left in the bag which is 100-a-b-c
* N, b! C/ C$ qTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。take the average of (100-a-b-c)
! y! V+ U; d. ?7 @公仔箱論壇then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)( W) N5 M0 ?% d- D
and number 4 can squeeze himself into the average and what number 5 picks.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。6 Y: ]7 F& @( {% i, g! w/ k: c
so number 4 will have the best chance.
5 I5 P* o$ V4 v: r' `% G& m
; r( G) j3 O2 C) R# D5.39.217.77:8898i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
| 