number 4 has the best chance to live
* T: Q# G; b- e% N# B: A公仔箱論壇assume number 1, 2, 3 and 4, pick number a, b, c and d.4 p4 B1 n) @7 d! Z# r
number 4 knows how many left in the bag which is 100-a-b-c
* T% @& U7 w) |* u! S2 ?/ K" j5 j* otake the average of (100-a-b-c)
( y# o! U% l) ?0 ]3 O- v6 Q. W5.39.217.77:8898then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
: d+ h0 k' h) n9 Q, Wtvb now,tvbnow,bttvband number 4 can squeeze himself into the average and what number 5 picks.
0 G" K/ Z8 w a* r$ V# o0 t; g+ Xso number 4 will have the best chance.tvb now,tvbnow,bttvb# v" p5 r4 h/ C* Y
* @ K8 C# a2 G& |i hope this is a good logic hehe |