number 4 has the best chance to live公仔箱論壇: w* T& ^9 M. W' l8 e0 M
assume number 1, 2, 3 and 4, pick number a, b, c and d.5 _+ y3 Y1 P5 g2 k$ ?
number 4 knows how many left in the bag which is 100-a-b-c
7 t0 K3 z! G3 e4 K% T$ b0 W" r3 T- Y公仔箱論壇take the average of (100-a-b-c)公仔箱論壇+ {5 R& A+ e9 O" V
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
) n8 b2 }, h' _5 o6 Z5 {. nand number 4 can squeeze himself into the average and what number 5 picks.# N x% h j5 v* E1 h. X
so number 4 will have the best chance.
g \% t1 h3 R, A; V" m5.39.217.77:8898tvb now,tvbnow,bttvb6 c, X4 ?7 {: e: r" q8 ?4 Z$ S5 ]. K& M
i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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