number 4 has the best chance to live! S5 b- V( j9 J4 O
assume number 1, 2, 3 and 4, pick number a, b, c and d.. l( {& L" S) P
number 4 knows how many left in the bag which is 100-a-b-c公仔箱論壇; z$ y$ N3 c$ a7 k. W- a) q, a6 y+ ?
take the average of (100-a-b-c)5.39.217.77:88983 u! ^1 I% [5 m2 z) z% g
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)tvb now,tvbnow,bttvb" I" S7 {0 ~6 C& r1 g6 d& ^
and number 4 can squeeze himself into the average and what number 5 picks.公仔箱論壇8 u/ `/ {& q3 o" u( p R
so number 4 will have the best chance.# P3 ^: g; x# G7 {/ k! K
5 N% C Q$ Q: Q5 p4 {8 k8 @5.39.217.77:8898i hope this is a good logic hehe |