number 4 has the best chance to live
( l9 j6 h8 B5 |7 f) K5.39.217.77:8898assume number 1, 2, 3 and 4, pick number a, b, c and d.
/ M# `4 e$ ^ e7 I3 k! |number 4 knows how many left in the bag which is 100-a-b-c
2 ?' K# N1 _. i! U. z+ ]4 jtake the average of (100-a-b-c)TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 g8 J8 ~' Z/ a" e" x4 i' t, s
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
& K5 @' [9 u9 y! B* t3 Y \公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.
( K/ X. k3 V ^7 t5 \- V9 J5.39.217.77:8898so number 4 will have the best chance.
3 F5 I3 j+ ^. O( t: @, t
# H( f# L& I# n6 Y- d) c1 D) l2 B公仔箱論壇i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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