number 4 has the best chance to live1 g8 u$ G7 v5 t( M" `+ t; Z, `
assume number 1, 2, 3 and 4, pick number a, b, c and d.# `. \) k* d2 W0 q S7 G4 _
number 4 knows how many left in the bag which is 100-a-b-c1 O, j) k2 T+ H& Y1 \5 V- c9 v
take the average of (100-a-b-c)TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。+ S3 c4 i% s u" `& u- P
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
2 z" y) g( l2 n3 r' j5 l. {and number 4 can squeeze himself into the average and what number 5 picks.$ C, M6 c3 L' }. R" d6 O
so number 4 will have the best chance.
2 C1 j; L% e/ D9 ]. z0 v公仔箱論壇
! ?5 _# E+ J( z3 J9 L公仔箱論壇i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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