number 4 has the best chance to live/ F9 G; R0 l! J, k8 j( g0 U) w1 Y
assume number 1, 2, 3 and 4, pick number a, b, c and d.
9 [8 I0 P; G; _% G- Snumber 4 knows how many left in the bag which is 100-a-b-c1 W, R+ I: y. e! |; Q
take the average of (100-a-b-c)tvb now,tvbnow,bttvb$ F; Q; ]- \& ~( O* l& j
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)公仔箱論壇& z" v. S: N& @! M, y# k
and number 4 can squeeze himself into the average and what number 5 picks.公仔箱論壇- G! H4 C6 `: b2 t+ j4 S
so number 4 will have the best chance.
8 c5 p/ `8 ^$ D# ?2 ~: atvb now,tvbnow,bttvb
[9 U1 j# s! Y/ l n7 }公仔箱論壇i hope this is a good logic hehe |