loveallcar

number 4 has the best chance to live5.39.217.77:8898: L7 l, d9 v/ t6 }2 P# V6 ~
assume number 1, 2, 3 and 4, pick number a, b, c and d.2 y! J9 \# _0 Y3 u& \; ~3 V
number 4 knows how many left in the bag which is 100-a-b-c' K; [. d; A4 J- R4 Q2 T
take the average of (100-a-b-c)5.39.217.77:8898! T) o0 v$ h; o
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)1 T, B, k: i7 J. {$ D
and number 4 can squeeze himself into the average and what number 5 picks.
, r( X8 {+ o! K$ ?. v( hTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。so number 4 will have the best chance.
+ ?8 {* z& y: |. a1 }; U5 [
. ?5 v* }! l' O( t公仔箱論壇i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.
6 \% `# F$ s" j& R% m公仔箱論壇please post answer la
; M/ ~1 r% ?+ TTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。can't wait la