number 4 has the best chance to liveTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 k: u: A7 M' M2 D
assume number 1, 2, 3 and 4, pick number a, b, c and d.
W k# Y' ~4 }: @3 h5.39.217.77:8898number 4 knows how many left in the bag which is 100-a-b-c5 ?) Q% e0 q3 o3 l; v
take the average of (100-a-b-c)
. {# {" [3 w5 }7 ATVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
& K- U1 m8 X( u& Cand number 4 can squeeze himself into the average and what number 5 picks.tvb now,tvbnow,bttvb# e4 l0 L% A! M7 k
so number 4 will have the best chance.tvb now,tvbnow,bttvb; u; {. X6 ~- a+ B! D/ o
5.39.217.77:8898+ l% Y0 _, N) h" ^9 Z7 }
i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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