loveallcar

number 4 has the best chance to live4 q7 Q" v3 L: Z+ F8 A6 d
assume number 1, 2, 3 and 4, pick number a, b, c and d.
9 [; X6 U* R: N( O3 ^$ W9 TTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。number 4 knows how many left in the bag which is 100-a-b-cTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。+ R  p" s( u# j( W2 V! y5 I
take the average of (100-a-b-c)4 k  N/ D  d( o5 p1 l, Y& R9 M
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。: z3 Z  s" C0 g4 }$ G/ @
and number 4 can squeeze himself into the average and what number 5 picks.
# [' x: N1 `, e2 U1 vso number 4 will have the best chance.
2 d- C$ M# x5 J/ R) d" O+ rtvb now,tvbnow,bttvb* D+ g2 i7 ]7 ]2 k% y/ L. }0 F: K5 D
i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.
2 M$ Y# ^+ ~# j3 ]; n; Mplease post answer la
" D3 A9 e4 m1 U% `" C' scan't wait la