另外,答案没有在题目里直接公布,不知道怎么隐藏,呵呵,所以只好先看看有没有人会了作者: bigpada 時間: 2009-8-27 09:43 AM
是1 2 3 5 \) y P9 C3 K5 h) z. s7 K3 C5.39.217.77:8898因为1的以外的所有正整数都是它的整数倍作者: Raymond92 時間: 2009-9-1 02:10 PM
好多答案啊``无聊的问题``作者: jamesdean 時間: 2009-10-2 06:55 AM
1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.作者: pengzw1984 時間: 2009-10-8 01:53 AM
249还有123作者: masami198763 時間: 2010-1-31 09:42 PM
123 and 789?作者: kuku88 時間: 2010-2-6 05:29 PM
three 1作者: ckpang 時間: 2010-2-7 11:05 PM
123.。。作者: cloud_FF 時間: 2010-2-9 02:16 AM
1 1 1作者: buxiang128 時間: 2010-2-9 09:55 AM
我列了个复杂的方程，但解不出了。不过如果不是1、1、1，楼主可能得注明是“三个不同的正整数”作者: khkiang 時間: 2010-2-12 03:13 AM
111, 789 ... and many many others.作者: beckyken 時間: 2010-2-12 01:48 PM
They would be 111 or 123 - r. Q2 S0 g1 T8 aFor 111 would be 1x1+1=2 that is 2 times of 3rd 1tvb now,tvbnow,bttvb7 h) {# i+ X0 J5 l8 K/ l
For 123 3 n( x! E5 s1 f( l, i; `. o公仔箱論壇1x2+1=3 that is 1 time of 3公仔箱論壇9 R8 `% Z' C, V! i. Q
1x3+1=4 that is 2 times of 2+ c H# I4 Z1 ?$ _0 c
2x3+1=7 thta is 7 times of 1
