標題: [IQ題] 2 Math related IQ problems [打印本頁] 作者: orotot 時間: 2012-4-6 04:00 AM 標題: 2 Math related IQ problems
I just read these last week. I hope these are new in here.5.39.217.77:8898: F8 [3 ^% R8 z1 q- z
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 {7 w; U( @9 ]% D& c5 y, ^2 n
#1) What is the next sequence?$ ]8 N) U Q5 X6 @" D% F
The numbers in this series describe how the previous number is formed. " t7 R: ?& Q h" R! j( }4 i7 U& t- j5 k7 u# g1 h" k7 h
The first no. is 1公仔箱論壇# }% {5 |' o# M% v1 N) M# q* k
The next one describe it: there is only one "1", therefore 11 , i' T8 B8 P/ j4 l0 jTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。The next one describe the "11" as there are two "1", therefore 21公仔箱論壇0 J5 K# d# u$ x+ l/ I' @
The next one describe the "21" as there are one "2" and one "1", therefore 1211 7 J! j: w* a: EThe next one describe the "1211" as there are one "1", one "2" and two "1", so 111221 / h* V- O4 G4 V. Y+ l. M9 STVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。The next one describe this "111221" is three "1", two "2" and one "1" so the answer is: $ V, J! K& M1 H$ C( M1 `- a312211 # W* |3 a! L t1 e- B) y公仔箱論壇 5 c9 H J( o8 u/ S公仔箱論壇I give up on question two.作者: irismylam 時間: 2012-6-23 08:40 AM
question 2 answer unavailable作者: gm3stevens 時間: 2012-6-23 11:35 AM
本帖最後由 gm3stevens 於 2012-6-23 06:56 PM 編輯 5 m8 c$ d7 o' s' S4 q) }
- d& `* ^- m; p* G5 c$ }公仔箱論壇After seeing the IQ question 據說這是蘋果公司的面試題, it reminds me of grouping the left hand side numbers to reflect the number on the right.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& |6 s# j" `1 e& `0 h
6 }) e4 s4 `" Q0 _& wSo the right hand side number 0 can be represented by number 1 5 o1 p' @# k$ O/ u* z( i6 u2 v5 xtvb now,tvbnow,bttvbThe right hand side number 1 can be represented by 3,1,2,9,7,5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" ^# ^4 B9 @& I2 {1 J8 w& Y5 m
The right hand side number 2 can be represented by 2,5,8,1,6,7,3,0/ f% u/ G7 }% U
The right hand side number 3 can be represented by 5,9,8,3 P' b% L; z0 ^6 z' zThe right hand side number 4 can be represented by 6 " @; u4 _5 y1 P- Z6 W1 e% xNow the question is 8136, check the above list, 8,1,3,6 are grouped under 2. Therefore, the answer is 2 V! Z6 A1 ]0 a+ C; |* p# S! Y# y' X公仔箱論壇+ Y# p3 \, o+ ]3 V+ k' n }
Sorry. My bad. Someone told me that it is actually counting the number of holes in the given number. tvb now,tvbnow,bttvb- K) v" [( m: o# z
There are 3 holes in 8136, two from number 8 and one from number 6 so the answer is 3.0 \- ?9 S& F: J- {6 p
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