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第2的....直覺告訴我
0000000000
友華
我已經想很久了
) G, n1 k: l7 a1 |! T3 T實在太難* |$ F% a4 l2 e$ ]) l
只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
, M3 h6 @& T( ]* `assume number 1, 2, 3 and 4, pick number a, b, c and d.
8 t' p) N) P' p公仔箱論壇number 4 knows how many left in the bag which is 100-a-b-c+ N7 {- u1 f; g
take the average of (100-a-b-c)5.39.217.77:88985 y, w6 d6 w( m1 e& T: Z
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
1 J5 R3 T6 k1 L3 Land number 4 can squeeze himself into the average and what number 5 picks.; u* D5 T7 k" A7 d4 q$ c' j
so number 4 will have the best chance.( N, t+ S( V8 {/ h/ R1 v+ z  a

  ^. b7 X' ]( u% E, xTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!公仔箱論壇7 L7 n6 E0 Z; h0 q5 X
玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!6 ^: P; {5 g, K, _. B

) R' D/ e: V5 U1 \* X; p1 K如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                   5.39.217.77:8898  ^# e1 n: {$ ^# c' I( u5 j

" Y3 J1 w4 H) l             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
! h$ ?) S% X: ]5.39.217.77:8898So they will all die !!                                                      5.39.217.77:88982 E0 c" ]: v# H3 c  J6 S3 c
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公仔箱論壇% y6 }: Q2 I" C5 X

% y8 f/ i, z, |4 b( ]5.39.217.77:8898" y" ?# V- G: w/ Y
公仔箱論壇# h: ?3 `' q( z0 f* D" r2 E* ]- p1 U
Just Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.5.39.217.77:88980 `$ {- r: P" s7 j& `
5.39.217.77:8898  b! X  B% W  m+ y" R) t
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
( f) K% V7 @% x: ]: D0 O5.39.217.77:8898
6 \4 f/ k# G! P2 CNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 u; u% A( T. |+ g' w2 k' [
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#3 did the obvious choice 40 divided by 2 =20, so he picked 20
  z! Y+ X$ u7 J' Q( v4 i公仔箱論壇5.39.217.77:88984 p/ T: r( X" I2 k% ]: K: g: Q
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.tvb now,tvbnow,bttvb" C- L" l- j8 d6 b# O( E/ e

9 P( M0 I7 b/ U0 p; F( B0 Y- D5 h公仔箱論壇#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.公仔箱論壇8 ^8 N7 y& A6 l

. S# d8 y, F. t. e' C公仔箱論壇Ended all have the same number and all died.
我猜NO4,TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- K8 X* |9 J' e1 U; B: ]) U( h
因為他可以取前面三位豆子的平均數,
( Q% E( Q2 b- S: i! P' j, j# C  vtvb now,tvbnow,bttvb也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
  \$ y$ Z4 `6 M1 @( Q; f* l5.39.217.77:88988 a1 a0 ~" m  E0 V" o! C8 q4 A- Q
[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,tvb now,tvbnow,bttvb; n- I7 m# w; f2 m. y; U
tvb now,tvbnow,bttvb+ n2 ~2 p8 V; W! G
答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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