The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.5.39.217.77:8898. d/ L( L# y6 g9 R U" R; A
* o7 u, n* K' O3 C. wStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.
9 S3 B$ O+ Z0 f9 r. W3 w; w5 ^
7 d: ]7 z! m# W' Q+ rtvb now,tvbnow,bttvbNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
0 d$ h8 n6 y0 ~" \6 y3 Z, Ztvb now,tvbnow,bttvb
7 l/ M& w1 i8 U( Y. \- `, e0 s! v* v8 P#3 did the obvious choice 40 divided by 2 =20, so he picked 205.39.217.77:8898% ?1 y$ B# B- R& b
tvb now,tvbnow,bttvb. Q( N% H$ ?# _6 A3 v
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。, A C, ?* ~% p+ k) ^
; Z( Y1 ?: d3 g4 r% _( c) xtvb now,tvbnow,bttvb#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
& k" J/ w0 v E# s- o5 G% W4 TTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。公仔箱論壇- k6 R! V' l3 |2 ^/ X1 l c
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
" S; S Q3 E k
