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第2的....直覺告訴我
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友華
我已經想很久了TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) `# C$ T, d$ {) |! s) d) r8 T
實在太難
( `  J7 Y' @& j+ t公仔箱論壇只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
8 Y; h5 b3 n( ~tvb now,tvbnow,bttvbassume number 1, 2, 3 and 4, pick number a, b, c and d.
2 L7 m' d: K3 Y! k, F1 V9 ynumber 4 knows how many left in the bag which is 100-a-b-ctvb now,tvbnow,bttvb. h. [- K/ c! T" |" s
take the average of (100-a-b-c)5.39.217.77:8898/ A: `( {( h% H) D* X
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)tvb now,tvbnow,bttvb6 d* M' Y9 T# Y/ V5 Z- T
and number 4 can squeeze himself into the average and what number 5 picks.
' L) S$ d/ i$ `5 D/ Rso number 4 will have the best chance.公仔箱論壇* ^" i% [' B0 n1 ?3 E. w+ \2 ?
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i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!* f( t6 l. t0 ]; f. Z0 s! J
玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!( i9 L; ~  g: |  c
公仔箱論壇4 N0 @' B+ X; ]% Y& {- X
如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                  
( @! S: \9 b, o7 N0 l/ o( X6 R2 k: ytvb now,tvbnow,bttvbTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- C! }0 ]8 v2 f3 Q; y9 U; p
             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18. tvb now,tvbnow,bttvb& G2 J$ q& ?6 Y4 ~
So they will all die !!                                                      公仔箱論壇4 l  A( J% ]' k! ]: m8 i% U$ C

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7 |+ M& x) ?6 Q公仔箱論壇
* y4 h/ f( s, A1 I0 G% w8 F% z  AJust Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.5 [; ?& A- b6 t) z& n- x8 }
5.39.217.77:88989 p+ A, V& d& ^/ U( R$ B4 T
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
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- a' P8 s5 |% i! Y5 j公仔箱論壇Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.  y' Y4 C4 t. \# X' G- V# P

- I) m+ J; T" K! L6 `1 _tvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20
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2 Q4 X4 e! m+ q- I) p& W7 F- }# q#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
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7 D3 ?1 g8 Y! V$ U* [: o2 I公仔箱論壇#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
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Ended all have the same number and all died.
我猜NO4,. [  o7 H, Z- G' Q+ h" s
因為他可以取前面三位豆子的平均數,
8 x; d: q6 ~7 O) a也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅公仔箱論壇0 O1 s4 A3 V* k5 J
5.39.217.77:8898( m: }* i4 _/ n. h! m
[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,
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( H. n& W) g0 S9 `' D) M公仔箱論壇答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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