The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.' o. p6 P3 f1 {) c5 s" m
5.39.217.77:8898/ i0 D1 q" c, \6 n7 o
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.
3 N2 D4 N% l3 I) mtvb now,tvbnow,bttvb' I! a5 e- E8 B6 ^6 Q3 C6 s. T
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
& G& f2 N, K7 o; p4 q3 N# W
, f, h6 G" w3 T5 [tvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20
. Q7 e+ T$ ?- P! y D vtvb now,tvbnow,bttvb
7 \" x: V$ T+ h8 y" \#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
( |2 l- z B- m' xTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
1 U9 _5 j5 W+ f7 A& r+ [) M公仔箱論壇#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
% `7 X* s6 v( R! `TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
' A) w! |0 \, f/ |2 _) m2 ?6 }3 I6 l. qTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
- |+ B) B6 H* ~: p1 \
