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第2的....直覺告訴我
0000000000
友華
我已經想很久了
' E, g7 `# G$ |9 o: b. x# o8 N公仔箱論壇實在太難
2 b2 {4 O/ A. E, ?, O; ^; g9 ^$ A只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live公仔箱論壇* p* t  K) V) r* i
assume number 1, 2, 3 and 4, pick number a, b, c and d.公仔箱論壇$ _& Q; O" N5 i5 W: F# I: j6 y
number 4 knows how many left in the bag which is 100-a-b-c( M# o) I( z' h2 ~
take the average of (100-a-b-c)
) C1 W2 K8 _& _# Z/ ?$ O% V5 |TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) o6 y8 P6 s" U1 I# m* V8 b
and number 4 can squeeze himself into the average and what number 5 picks." {7 I5 n3 d4 A+ b3 V' r
so number 4 will have the best chance.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5 B; g8 Y  N- T

  @4 @6 T" ~' [) Z/ E5.39.217.77:8898i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!$ D, C( ?1 O1 k3 h- }' B3 d- c
玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!tvb now,tvbnow,bttvb1 R, ]$ ]5 L; [8 u8 n4 v" K! {

+ @; i9 j1 a' J& D; y  }: f  N- n公仔箱論壇如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                  
! u, @8 i  J5 S6 A/ A8 ?TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。
) _4 `6 X) Y4 Z1 S0 W; b( K: f             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
: t* ]( o* A5 R3 b; x) J6 ~/ j2 xSo they will all die !!                                                      tvb now,tvbnow,bttvb8 |7 A" k! V/ K1 M
公仔箱論壇. L7 X- f5 K1 p& j# L. C4 n* |" c
tvb now,tvbnow,bttvb' t/ A, q' y& B8 L

6 r3 j7 L  r/ d5.39.217.77:8898
4 u2 ^2 |7 N- \: d
6 t! E" G% {( m+ ~) B; l公仔箱論壇Just Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.2 p( [) x$ k4 E4 ^: M2 J0 Z
公仔箱論壇0 V% |" _2 Z! t
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  5.39.217.77:8898$ N* O8 u" i& }# q& Z- b$ g

" J  x3 ~  w9 l9 fTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.公仔箱論壇9 K* q. I" V2 @9 [

6 H8 j" x# w- O3 _& U#3 did the obvious choice 40 divided by 2 =20, so he picked 20
" [: G" x6 @' b  F* M6 h) S; gTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。  ~" D1 [" Y' D4 J' m* W
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
7 J4 B# s" l( j  v0 W
1 a+ L4 `$ a1 }; |/ rtvb now,tvbnow,bttvb#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.5.39.217.77:8898+ D: q9 K8 A6 D6 D7 H
tvb now,tvbnow,bttvb1 J# p6 `+ o; T2 U6 X" a) m
Ended all have the same number and all died.
我猜NO4,
" X- h2 E3 J9 u5.39.217.77:8898因為他可以取前面三位豆子的平均數,
/ Q# P; d& x3 R5 |也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
* P1 [# t3 v/ |, C& l# _4 KTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。( e, k; z6 e4 s7 Z
[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,
, Z* D" P$ R3 {9 P' J公仔箱論壇4 j+ O$ K9 \- L' x
答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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