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第2的....直覺告訴我
0000000000
友華
我已經想很久了tvb now,tvbnow,bttvb! B8 @& `% v3 |6 z( I( s) j
實在太難
* C* s7 @) y/ ~3 q* _tvb now,tvbnow,bttvb只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
0 I, m) L* x  q$ `+ v, n9 F5.39.217.77:8898assume number 1, 2, 3 and 4, pick number a, b, c and d.
3 b8 W/ n) O) O+ f  ]$ {! `number 4 knows how many left in the bag which is 100-a-b-c
4 x& W( M  F* }% X' |2 ktvb now,tvbnow,bttvbtake the average of (100-a-b-c)
: Y, {2 h2 I, [, I# h+ G7 x5.39.217.77:8898then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)2 v( ^8 e" H$ r' R2 b4 H, y, |
and number 4 can squeeze himself into the average and what number 5 picks.
+ x' P9 B0 k2 p5 j6 U公仔箱論壇so number 4 will have the best chance.
2 E4 p: L: J' q% L$ @5.39.217.77:8898
) t! L1 n2 _# a& [i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!
0 V+ ^6 \/ |# c8 x& p公仔箱論壇玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!
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如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                   公仔箱論壇6 C0 Z( H" b  _; _

  a8 s: X1 c" ~4 s* I             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
) A. @: O! v7 @6 i公仔箱論壇So they will all die !!                                                      公仔箱論壇' R1 I, ]# f& R7 S  W& i* q- j& y
tvb now,tvbnow,bttvb* R) a5 E% ^  E4 w  P" q# ]

! P8 |  H$ Y4 F$ `tvb now,tvbnow,bttvb6 i' F9 ^9 _* K+ I# Z/ Q
! Y( V9 N+ W9 ?2 [+ S* _
5.39.217.77:88981 w- v+ c/ N! g
Just Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
  k) R  b  A0 q1 hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% L) u& s  }3 s' z& i
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
) c, F' q  a# b8 n8 [3 N  s4 a' ]tvb now,tvbnow,bttvb  n4 C, u4 F+ T0 ^% K
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
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& L3 a: Q- p$ h1 {% b  T, Htvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20
0 d& ?5 T4 P9 K: ]3 x+ E% jtvb now,tvbnow,bttvb
: b; _, S9 w9 O( I, @5 a3 I#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
% z0 g9 C/ P2 Y. u5.39.217.77:8898TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ M2 o. l: f! r: Z# \8 ~
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.5.39.217.77:8898+ B5 Z" W) m! M

1 r- h- K$ Y2 r" {1 h- x% @TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Ended all have the same number and all died.
我猜NO4,& n+ n* \* ^& m
因為他可以取前面三位豆子的平均數,
" i- J; Q* l  ]  L8 m0 n也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
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, V" J4 ]8 S4 X3 G8 @# J2 a5.39.217.77:8898[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,
! ^* G* E- {3 |) D# B9 i5.39.217.77:8898- `6 l8 Z1 D, g! @1 H' |
答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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