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第2的....直覺告訴我
0000000000
友華
我已經想很久了
) Y0 F5 f! C( K: d  Q4 f# Q7 F  w/ k公仔箱論壇實在太難
' H2 A9 w) M1 T公仔箱論壇只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live, x3 G- f3 t+ R
assume number 1, 2, 3 and 4, pick number a, b, c and d.$ c6 z) ]# m/ b  ~3 B
number 4 knows how many left in the bag which is 100-a-b-c
2 B- h4 o8 o: A+ @9 J* l5.39.217.77:8898take the average of (100-a-b-c)5.39.217.77:88989 x* _9 J' J! S4 B  w6 y8 Q( P
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
* ?- i5 e1 L+ h0 m  V: A0 ]& m6 X5.39.217.77:8898and number 4 can squeeze himself into the average and what number 5 picks.
: c2 w9 U7 K& [4 h  d9 W+ pTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。so number 4 will have the best chance.
& j( N5 O. l. ~" F5 w& w1 f5.39.217.77:8898
3 k6 a+ x1 b* v5 x, U7 e* H* G公仔箱論壇i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!
" x- {3 l+ ?+ k  \( C3 }: d; Y, A公仔箱論壇玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2 a2 L' }" L% H8 d: ^

- y  i+ f7 _7 y5 I* F如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                   TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。; y1 M: b& y) P
公仔箱論壇) j2 ~5 ]/ B9 ]  r2 P- y
             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
9 U8 B7 l5 P, [9 e3 L! X9 P公仔箱論壇So they will all die !!                                                      
% ~& g4 g: Y: W4 h% q: {TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 H' F: ?/ U7 k* f, E! C% e
5.39.217.77:88986 X9 S  }2 ^  b0 ]8 j( t

/ T7 N: [' ]' ?8 m2 }tvb now,tvbnow,bttvb公仔箱論壇' t8 e# c7 F7 c4 B2 \  V

4 m7 q; P7 G. U5 v; A* V4 wJust Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
3 S% w& t, \1 |+ t) m! O+ o  c2 h2 _/ \
9 ^' q! U# A  n4 L2 Z, BStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
! l6 O$ L  a; j% @8 oTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 u' s! Q# j& C4 J0 e
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.) j2 M  w( @/ z1 B3 Q. N7 B& M2 F

5 p1 u$ T' n8 [( _tvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20
, P: H  A/ e; H* R* G# p' F- j$ [tvb now,tvbnow,bttvb5.39.217.77:8898& u+ w: w! l, x) X
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.% F$ V0 y: P/ M' w. R

9 a& l% T" Q( s5 u- A* b  C5.39.217.77:8898#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.6 S; S/ S0 W7 W+ T( F3 ]

: k* z$ K- K- ^2 p% X2 STVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Ended all have the same number and all died.
我猜NO4,5.39.217.77:8898; o2 x- h: z2 [/ W  g+ Y
因為他可以取前面三位豆子的平均數,
! }! j7 H, N, Z/ E5.39.217.77:8898也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
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' R1 p8 O8 r' X+ ~" F" ?! j  N[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,
: k+ {" e( `( lTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。
' v  N0 a8 M  q+ p3 e1 C) Y5.39.217.77:8898答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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