1. divide 6 and 6, both sides will not equal % P! M$ I ~! M/ q2 @- b R2. take any side of the 6, divide then 3 and 3, again both sides will not equal+ c7 ~4 r' @1 F2 o. s: ]
3. take any 2 and weigh them + I7 @7 b6 r) d5.39.217.77:8898if they equal, the one left is the ball.