put six on each side first
F/ U0 @5 I7 f' b# Qtvb now,tvbnow,bttvb
) x( \! m! q% T) N( |' B5.39.217.77:8898from the heavier six, split it to three on each side
6 l4 P: f# s; u# _5.39.217.77:8898
* g( C% b- ]7 c9 y5 w7 ~tvb now,tvbnow,bttvbthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |